(Postgres 9.4)我有一个返回整数 4 的简单查询,然后我捕获该数字并循环遍历if语句并返回编辑结果。答案应该是 4分钟,但我一直 4周。由于某种原因,这不起作用,例如这是我的代码
library(ggplot2)
DF <- data.frame(v1=c(5, 10, 15, 20, 25, 30), v2=c(2, 3, 1, 3, 4, 2))
p <- ggplot(DF) + geom_bar(aes(x=v1, y=v2),stat="identity")
p <- p + theme_classic()
p <- p + labs(title='Chart Title', x='series 1', y='')
p
我正在使用 System.err.println(差异(rs.getInt(“fire”))); 来跟踪结果。我怎样才能完成这项工作或有更好的方法来实现这一目标?
答案 0 :(得分:3)
if-else语句中有错误。尝试以下
try {
Connection con = null;
ResultSet rs;
con=DB.getConnection();
// this fire returns as an Integer 4
PreparedStatement ps =con.prepareStatement("SELECT EXTRACT
(EPOCH FROM(last_reply-created_on)/60):: integer as fire from streams where id=65");
rs= ps.executeQuery();
while (rs.next()) {
// I then put this method through
System.err.println(difference(rs.getInt("fire")));
}
con.close();
return ok();
} catch (Exception e) {
System.err.println(e.getMessage());
}
private static String difference(Integer i) {
String id="";
if(i<60)
{
4 is obviously less than 60 but it is not working
id= i+ " min";
}else if(i>=60 && i<1440)
{
id=i+ " hrs";
}else if(i>=1441 && i<10080)
{
id=i+" days";
}
else
{
id=i+" weeks";
}
// returns as 4 date
return id;
}