Question

我遵循Google API文档并尝试查找当前设备周围的位置。我正在尝试使用GMSPlacesClient.currentPlaceWithCallback。

文档示例是

GMSPlacesClient.currentPlaceWithCallback({ (placeLikelihoods: GMSPlaceLikelihoodList,error) -> Void in
        if error != nil {
            println("Current Place error: \(error.localizedDescription)")
            return
        }

        for likelihood in placeLikelihoods.likelihoods {
            if let likelihood = likelihood as? GMSPlaceLikelihood {
                let place = likelihood.place
                println("Current Place name \(place.name) at likelihood \(likelihood.likelihood)")
                println("Current Place address \(place.formattedAddress)")
                println("Current Place attributions \(place.attributions)")
                println("Current PlaceID \(place.placeID)")
            }
        }
    })

然而，它失败了构建错误无法使用类型'（（GMSPlaceLikelihoodList，_） - ＆gt; Void）'的参数列表调用'currentPlaceWithCallback'

建议请...谢谢

Answer 1

您可以在placeLikelihoods之后删除“：GMSPlaceLikelihoodList”，它应该可以正常工作。对于我使用的所有GMSPlaceClient方法，您不需要在回调中包含参数类型

Answer 2

swift 3，xcode 8.1

这是我的代码段，在通过CocoaPods添加GooglePlaces之后，请确保您已声明let var placesClient: GMSPlacesClient?并获得CLLocationManager的授权

placesClient?.currentPlace(callback: { (placeLikelihoodList, error) in
    if error != nil {
        print("Current Place error: \(error!.localizedDescription)")
        return
    }

    if let placeLicklihoodList = placeLikelihoodList {
        let place = placeLicklihoodList.likelihoods.first?.place
        if let place = place
        {
            print("Current Place address \(place.formattedAddress)")
            print("Current Place attributions \(place.attributions)")
            print("Current PlaceID \(place.placeID)")
        }
    }
})

代码工作正常，但仍然显示错误，“操作无法完成.Parks API库中发生内部错误”。但至少，它可以建立。

使用XSP 6.4在swift中使用GMSPlacesClient时出错

2 个答案: