在我的angular-app中，我有3个查询，每个查询都取决于其他查询。我将promise()放在每个人身上。在这种情况下，我怎样才能获得所有这些依赖的承诺$q.all？
有人可以为我澄清这个吗？
这是我的代码：
"use strict";
angular.module("tcpApp")
.controller("projectSummaryController",
['$scope', '$routeParams', '$location', 'server', 'modalService', '$q',
function ( $scope, $routeParams, $location, server, modalService, $q ) {
$scope.projectId = $routeParams.projectId;
$scope.subProjectId = $routeParams.subProjectId;
$scope.phaseId = 0;
$scope.disciplineId = 0;
$scope.contractorId = 0;
$scope.queryConractorInfo = function ( contractorId ) {
server.contractorInfo.get({
projectId:$scope.projectId,
subProjectId : $scope.subProjectId,
contractId : $scope.contractorId,
disciplineId : $scope.disciplineId,
staticId : 0 /* at present static */
}).$promise.then(function ( contractorInfo ) {
$scope.contractorInfo = contractorInfo;
})
}
$scope.queryConractorList = function ( phaseId, disciplineId ) {
var base = 'http://azvsptcsdev02:678/_vti_bin/CPMD.WEBSERVICE/ProjectInfoService.svc/Contracts/'
console.log( base+$scope.projectId+'/'+$scope.subProjectId+'/'+phaseId+'/'+disciplineId );
server.contractorsList.query(
{
projectId:$scope.projectId,
subProjectId : $scope.subProjectId,
phaseId : phaseId,
disciplineId: disciplineId
}).$promise.then(function ( contractorsList ) {
$scope.contractorId = contractorsList[0].Id; //setting the first contractor as default;
$scope.queryConractorInfo( $scope.contractorId );
});
}
$scope.queryProject = function ( prjId, subPrjId ) {
server.projectSummary.get({id:$scope.projectId})
.$promise.then(function (data) {
//only setting phase id and desciple id to get list of contractors
$scope.phaseId = data.PhaseIds[0].Id; //setting the first phase as default;
$scope.disciplineId = data.DisciplineIds[0].Id; //setting the first descipline as default;
$scope.queryConractorList( $scope.phaseId, $scope.disciplineId );
});
}
if($scope.projectId) {
$scope.queryProject();
}
$q.all([ $scope.queryProject, $scope.queryConractorList, $scope.queryConractorInfo ])
.then(function ( data1, data2, data3 ) {
console.log( data1, data2, data3 );// i get nothing here!
})
}]);
处理此问题的最佳做法是什么？