我试图做一个简单的GET请求(使用修改后的User-Agent),返回对QML的响应并进行JSON解析。
实际上它只在加载完成时返回页面内容,但它不会将其返回到QML。
抱歉这个菜鸟问题。我是这种语言的新手,我正在努力学习它:)
这是我的代码:
Home.qml
function getRequest() {
[...]
console.log('Request...')
var jsonResult = JSON.parse(connectNet.connectUrl("http://myURL.com/index.php").toString())
lbOutput.text = jsonResult.predictions[0].description.toString()
}
}
connectnet.cpp
#include "connectnet.h"
#include "stdio.h"
#include <QDebug>
#include <QNetworkRequest>
#include <QNetworkReply>
#include <QNetworkAccessManager>
#include <QUrl>
connectNet::connectNet(QObject *parent) : QObject(parent)
{
}
void connectNet::connectUrl(QString url)
{
QNetworkAccessManager *manager = new QNetworkAccessManager();
QNetworkRequest request;
QNetworkReply *reply = NULL;
request.setUrl(QUrl(url));
request.setRawHeader( "User-Agent" , "FAKE USER AGENT HERE" );
reply = manager->get(request);
connect(manager, SIGNAL(finished(QNetworkReply*)), this,
SLOT(replyFinished(QNetworkReply*)));
}
QString connectNet::replyFinished(QNetworkReply *reply)
{
return reply->readAll();
}
appname.cpp
#ifdef QT_QML_DEBUG
#include <QtQuick>
#endif
#include <sailfishapp.h>
#include "connectnet.h"
int main(int argc, char *argv[])
{
//INIT SETTINGS
QGuiApplication *app = SailfishApp::application(argc, argv);
QQuickView *view = SailfishApp::createView();
connectNet ConnectNet;
view->rootContext()->setContextProperty("connectNet", &ConnectNet);
view->setSource(SailfishApp::pathTo("qml/APPNAME.qml"));
view->showFullScreen();
app->exec();
}
希望我能很好地解释我在寻找什么。谢谢你的帮助。
编辑20/08/2015:添加了更新的connectnet.h
#ifndef CONNECTNET_H
#define CONNECTNET_H
#include <QObject>
#include <QNetworkReply>
#include <QDebug>
#include <QNetworkRequest>
#include <QNetworkReply>
#include <QNetworkAccessManager>
#include <QUrl>
class ConnectNet : public QObject
{
Q_OBJECT
QNetworkAccessManager m_manager;
public:
ConnectNet(QObject * parent = 0) : QObject(parent) {
connect(&m_manager, &QNetworkAccessManager::finished,
[this](QNetworkReply * reply) {
if (reply->error() == QNetworkReply::NoError)
emit replyAvailable(QString::fromUtf8(reply->readAll()));
});
}
signals:
void replyAvailable(const QString & reply);
public slots:
void sendRequest(const QString url) {
QNetworkRequest request;
request.setUrl(QUrl(url));
request.setRawHeader("User-Agent", "MyLittleAgent");
m_manager.get(request);
}
};
#endif // CONNECTNET_H
这段代码会产生很多错误:((下面的截图)
connect(&m_manager, &QNetworkAccessManager::finished,
[this](QNetworkReply * reply) {
if (reply->error() == QNetworkReply::NoError)
emit replyAvailable(QString::fromUtf8(reply->readAll()));
});
答案 0 :(得分:5)
你的问题是你同步思考。 connectUrl
无法返回值(并且它不会返回),因为当它运行时,结果不可用。相反,你必须做的是ConnectNet
类在数据可用时发出信号。
如果您尝试制作一个确实返回值的同步包装器,那将是一个可怕的想法:只要接收到结果,QML引擎就会被卡住。您可以在合适的时刻拉动网络电缆,或者如果服务器已关闭,则可以冻结您的应用程序。用户讨厌这一点,而且这是一个可怕的反模式,必须适当地消除和劝阻。
以下是ConnectNet
(请,不是connectNet
,小写名称适用于成员!)类可以查看的内容。请注意,QNetworkAccessManager
实例不需要是指针。
class ConnectNet : public QObject {
Q_OBJECT
QNetworkAccessManager m_manager;
public:
ConnectNet(QObject * parent = 0) : QObject(parent) {
connect(&m_manager, &QNetworkAccessManager::finished,
[this](QNetworkReply * reply) {
if (reply->error() == QNetworkReply::NoError)
emit replyAvailable(QString::fromUtf8(reply->readAll()));
});
}
Q_SLOT void sendRequest(const QString & url) {
auto request = QNetworkRequest(QUrl(url));
request.setRawHeader("User-Agent", "MyLittleAgent");
m_manager.get(request);
}
Q_SIGNAL void replyAvailable(const QString & reply);
};
由于connectNet
实例实例在全局QML上下文中作为属性公开,因此您可以按如下方式连接到其信号:
function getRequest() {
connectNet.sendRequest("http://myURL.com/index.php")
}
function resultHandler(result) {
var jsonResult = JSON.parse(result.toString())
lbOutput.text = jsonResult.predictions[0].description.toString()
}
Rectangle { // or any other item
Component.onCompleted: {
connectNet.replyAvailable.connect(resultHandler)
}
...
}