Question

＆＃13;

public class DbHelper extends SQLiteOpenHelper {
  
    private static final String DATABASE_NAME = "assignment_info.db";

    public static final String ASSIGNMENT_ID  = "_id";
    public static final String ASSIGNMENT_VALUE = "assignment_value";
    public static final String ASSIGNMENT_RESULT = "assignment_result";
    public static final String SUBJECT = "subject";
    public static final String ASSIGNMENT_TITLE = "assignment_title";
    public static final String DUE_DATE = "due_date";
    public static final String NOTES_ASSIGNMENT = "notes";
    public static final String TABLE_NAME_ASSIGNMENT = "assignment_information";

    private static final String ADD_QUERY = "CREATE TABLE "+
            TABLE_NAME_ASSIGNMENT+"("+
            ASSIGNMENT_ID+" INTEGER PRIMARY KEY AUTOINCREMENT,"+
            SUBJECT+" TEXT,"+
            ASSIGNMENT_VALUE+" INTEGER,"+
            ASSIGNMENT_RESULT+" DOUBLE,"+
            ASSIGNMENT_TITLE+" TEXT,"+
            DUE_DATE+" DATE,"+
            NOTES_ASSIGNMENT+" TEXT);";


    public DbHelper(Context context){

        super(context,DATABASE_NAME,null,DATABASE_VERSION);
        Log.e("Database Operations","Database opened/created from constructor.");
    }

    @Override
    public void onCreate(SQLiteDatabase db) {
        //IF DATABASE IS CREATED FOR FIRST TIME THIS METHOD WILL BE CALLED
        db.execSQL(ADD_QUERY);
        db.execSQL(ADD_NOTES_QUERY);
        Log.e("Database Operations"," DbHelper - onCreate called ");

    }

＆＃13;

我有一个SQLite表，其中包含存储为字符串＆gt;＆gt;
的日期＆＃34; + DUE_DATE +＆＃34; STRING，＆＃34; 。

我想选择今天日期和现在7天之间的所有行。

这是我到目前为止所做的，它不会返回任何结果，

    String sql = "SELECT * FROM " + TABLE_NAME_ASSIGNMENT + " WHERE "+ DUE_DATE + " >= date('now') AND date('now','+7 days')";

任何人都可以帮忙吗？感谢

创建表TABLE_NAME_ASSIGNMENT （ASSIGNMENT_ID INT，SUBJECT文字，ASSIGNMENT_TITLE文字，DUE_DATE日期） ;

插入TABLE_NAME_ASSIGNMENT （ASSIGNMENT_ID，SUBJECT，ASSIGNMENT_TITLE，DUE_DATE） VALUES （1，＆＃39; MATHS＆＃39;，＆＃39; Prime Numbers＆＃39;，＆＃39; 2015-08-22＆＃39;），（2，＆＃39;科学＆＃39;，＆＃39;周期表＆＃39;，2015-08-30＆＃39;），（3，＆＃39; MATHS＆＃39;，＆＃39; Odd Numbers＆＃39;，＆＃39; 2015-09-02＆＃39;） ;

选择 *

这 TABLE_NAME_ASSIGNMENT

截止日期（＆＃39;现在＆＃39;）和日期（＆＃39;现在＆＃39;，＆＃39; +7天＆＃39;）

您的SQL语法有错误;查看与您的MySQL服务器版本对应的手册，以获得正确的语法，以便在＆＃39; + 7天后使用＆＃39;）＆＃39;在第10行

Answer 1

您是否尝试过使用BETWEEN？

String sql = "SELECT * FROM " + TABLE_NAME_ASSIGNMENT + " WHERE "+ DUE_DATE + " BETWEEN date('now') AND date('now','+7 days')"

还要确保DUE_DATE是YYYY-MM-DD格式的DATE类型

Answer 2

在表中，您将日期存储为字符串类型，因此除非在执行查询时以实际日期格式转换日期字符串，否则无法以传统方式检索数据。请使用以下查询再试一次。

SELECT 
 * 
FROM 
 Mytable 
WHERE 
 DATE(substr(fecha ,1,4) ||substr(fecha ,6,2)||substr(fecha ,9,2))
BETWEEN 
 DATE(20140105) 
AND 
 DATE(20140105);

如何从今天的日期和7天时间之间的SQLite表中选择行

2 个答案: