Question

我正在尝试使用spring security csrf对我的webservice发出一个HttpPost。

首先，我试图通过GET请求恢复XSRF TOKEN，就像这样

public static CookieManager xcsrfToken() throws IOException{
    String token;
    URL url = new URL(urlBase);
    HttpURLConnection con = (HttpURLConnection) url.openConnection();
    con.setRequestMethod("GET");
    CookieManager cookieManager = new CookieManager();
    con.connect();

    List<String> cookieHeader = con.getHeaderFields().get("Set-Cookie");

    if (cookieHeader != null) {
        for (String cookie : cookieHeader) {
            cookieManager.getCookieStore().add(null, HttpCookie.parse(cookie).get(0));
        }
    }
    System.out.println(con.getHeaderFields());
    con.disconnect();

    return cookieManager;
}

这是我从con.getHeaderFields（）

获得的

{null=[HTTP/1.1 200 OK], Cache-Control=[no-cache, no-store, max-age=0, must-revalidate], Content-Language=[pt-BR], Content-Length=[973], Content-Type=[text/html;charset=ISO-8859-1], Date=[Wed, 19 Aug 2015 10:40:18 GMT], Expires=[0], Pragma=[no-cache], Server=[Apache-Coyote/1.1], Set-Cookie=[JSESSIONID=6C9326FBEEA14752068720006F2B5EAA; Path=/webapi/; HttpOnly, XSRF-TOKEN=07cbed7f-834e-4146-8537-0a6b5669f223; Path=/], X-Android-Received-Millis=[1439980819720], X-Android-Response-Source=[NETWORK 200], X-Android-Sent-Millis=[1439980819693], X-Content-Type-Options=[nosniff], X-Frame-Options=[DENY], X-XSS-Protection=[1; mode=block]}

XSRF-TOKEN在我的cookie中，好的！如果我打印然后用的System.out.println（cookieManager.getCookieStore（）的getCookies（））; 我得到了这个

[JSESSIONID=5B1D3E2D3E7B3E1E6572A3839BFF3741, XSRF-TOKEN=4d4048bd-f21c-48c6-895e-5f67523ad963]

现在，我正在尝试针对服务器发出POST，就像这样

public static HttpURLConnection makeRequest(String metodo, String uri, String requestBody) throws IOException{
    URL url = new URL(urlBase + uri);
    HttpURLConnection con = (HttpURLConnection) url.openConnection();
    con.setRequestMethod("POST");

    con.setDoInput(true);
    con.setDoOutput(!metodo.equals("GET"));
    con.setRequestProperty("Content-Type", "application/json");
    con.setRequestProperty("Cookie", TextUtils.join("," , xcsrfToken().getCookieStore().getCookies()));

    con.connect();

    InputStream is = con.getErrorStream();
    System.out.println(IOUtils.toString(is, "UTF-8"));

    System.out.println(con.getHeaderFields());

    return con;
}

但是标题在没有cookie的情况下回来了

 {null=[HTTP/1.1 403 Forbidden], Cache-Control=[no-cache, no-store, max-age=0, must-revalidate], Content-Language=[en], Content-Length=[1149], Content-Type=[text/html;charset=utf-8], Date=[Wed, 19 Aug 2015 10:42:18 GMT], Expires=[0], Pragma=[no-cache], Server=[Apache-Coyote/1.1], X-Android-Received-Millis=[1439980939827], X-Android-Response-Source=[NETWORK 403], X-Android-Sent-Millis=[1439980939811], X-Content-Type-Options=[nosniff], X-Frame-Options=[DENY], X-XSS-Protection=[1; mode=block]}

它说没有CSRF有效令牌

Invalid CSRF Token 'null' was found on the request parameter '_csrf' or header 'X-XSRF-TOKEN'.

在我的网络服务中，由于angularJs，令牌被配置为重命名为XSRF-TOKEN。

解

public static void getTokens() throws IOException{
    URL url = new URL(urlBase);
    HttpURLConnection con = (HttpURLConnection) url.openConnection();
    con.setRequestMethod("GET");
    con.connect();
    cookieManager = new CookieManager();

    List<String> cookieHeader = con.getHeaderFields().get("Set-Cookie");

    if (cookieHeader != null) {
        for (String cookie : cookieHeader) {
            String[] tokens = TextUtils.split(cookie, "=");
            if (tokens[0].equals("JSESSIONID"))
                cookieManager.getCookieStore().add(null, HttpCookie.parse(cookie).get(0));
            if (tokens[0].equals("XSRF-TOKEN")) {
                String[] tokenValue = TextUtils.split(tokens[1],";");
                xsrfTOKEN = tokenValue[0];
            }
        }
    }

    con.disconnect();
}

然后，将其附加到HttpUrlConnection

con.setRequestProperty("X-XSRF-TOKEN", xsrfTOKEN);

Answer 1

根据我的经验，我们需要将令牌作为请求提交标题。 Spring默认其名称为X-XSRF-TOKEN。但是使用AngularJS的人通常会在Spring Security配置中将其更改为if (xsrfToken != null && !ctx.getRequestMethod().equals(Method.GET)) requestSpec.header("X-XSRF-TOKEN", xsrfToken);。

但是看看你的代码，我无法弄清楚你是否正在发送这个标题。

如果有帮助，这是我的一个项目的片段（使用 RestAssured ）：

ExternalInterface.call("recordScore()”);

Android HttpUrlConnection无法发布 - 错误403

1 个答案: