Question

您好我想创建一个后台服务，该服务将在每天的特定时间重复以从服务器更新数据，直到现在我有这个代码：

public class Service_class extends Service {


@Override
public IBinder onBind(Intent arg0) {
    return null;
}

@Override
public int onStartCommand(Intent intent, int flags, int startId) {
    Toast.makeText(this, "Service Started", Toast.LENGTH_LONG).show();
    return START_STICKY;
}

@Override
public void onDestroy() {

    super.onDestroy();
    Toast.makeText(this, "Service Stopped", Toast.LENGTH_LONG).show();

}

@Override
public void onCreate() {
    super.onCreate();
}

}

我在main

中使用此代码启动服务

startService(new Intent(getBaseContext(), Service_class.class));

如何让我的服务在每天的确切时间重复，即使应用程序关闭也不会停止？谢谢

Answer 1

您可以使用AlaramManager，如下所示

AlarmManager am = (AlarmManager)context.getSystemService(Context.ALARM_SERVICE);

Intent i = new Intent(context, Alarm.class);
PendingIntent pi = PendingIntent.getBroadcast(context, 0, i, 0);
am.set(AlarmManager.RTC_WAKEUP, System.currentTimeMillis() + (1000 * 60 * 10), pi);

// Millisec * Second

Answer 2

您可以将 AlarmManager 类用于此

Intent alarmIntent = new Intent(context, Service_class.class);
    pendingIntent = PendingIntent.getBroadcast(context, 0, alarmIntent, 0);
    AlarmManager manager = (AlarmManager) context
            .getSystemService(Context.ALARM_SERVICE);
    int interval = 60*60*24;//number of seconds
    manager.setInexactRepeating(AlarmManager.RTC_WAKEUP,
            System.currentTimeMillis(), interval, pendingIntent);

Answer 3

我也有同样的要求。我遵循以下程序。在您的服务onCreate()

中

＆＃13;

Intent alarmIntent=new Intent(this,AlarmHandle.class);
PendingIntent pendingIntent = PendingIntent.getBroadcast(this, 0, alarmIntent, 0);
AlarmManager manager = (AlarmManager) getSystemService(Context.ALARM_SERVICE);
int interval = 86400*1000; // for getting called every 24 hours 
manager.setInexactRepeating(AlarmManager.RTC_WAKEUP, System.currentTimeMillis(), interval, pendingIntent);

＆＃13;

此处AlarmHandle类扩展了BroadcastReceiver。在提到的时间间隔值期间，将调用此接收器的onReceive。

确保AndroidManifest文件中的receiver标记提及AlarmHandle。

＆＃13;

<receiver android:name=".AlarmHandle">
</receiver>

＆＃13;

背景服务与重复时间

3 个答案: