Question

在hibernate 4 - spring 4设置中，可以使用SchemaExport对象生成DDL：

LocalSessionFactoryBean sfb = (LocalSessionFactoryBean) context.getBean("&sessionFactory");
SchemaExport schema = new SchemaExport(sfb.getConfiguration());

但是hibernate 5用SchemaExport(Configuration configuration)替换SchemaExport(MetadataImplementator metadataImplementator)构造函数。

上没有 org.springframework.orm.hibernate5.LocalSessionFactoryBean或org.springframework.orm.hibernate5.LocalSessionFactoryBuilder

我这样砍了它：

MetadataSources metadataSources = (MetadataSources) FieldUtils.readField(configuration, "metadataSources", true);


Metadata metadata = metadataSources
    .getMetadataBuilder(configuration.getStandardServiceRegistryBuilder().build())
    .applyPhysicalNamingStrategy(new MyPhysicialNamingStrategy())
    .applyImplicitNamingStrategy(ImplicitNamingStrategyJpaCompliantImpl.INSTANCE)
    .build();

MetadataImplementor metadataImpl = (MetadataImplementor) metadata;
SchemaExport schema = new SchemaExport(metadataImplementor);

但是有一个更好的方法会很好，而且，Validator注释（@NotNull，@ Size）不用于DDL生成，我不知道它是否是Hibernate 5或此设置中的错误。< / p>

我正在使用hibernate 5.0.0.CR4 和spring 4.2.0.RELEASE

Answer 1

您需要实施org.hibernate.integrator.spi.Integrator，您可以将所需数据存储到某个持有者。

您可以在此处找到工作示例https://github.com/valery-barysok/spring4-hibernate5-stackoverflow-34612019

将其注册为META-INF/services/org.hibernate.integrator.spi.Integrator文件

的服务

public class Integrator implements org.hibernate.integrator.spi.Integrator {

    @Override
    public void integrate(Metadata metadata, SessionFactoryImplementor sessionFactory, SessionFactoryServiceRegistry serviceRegistry) {
        HibernateInfoHolder.setMetadata(metadata);
        HibernateInfoHolder.setSessionFactory(sessionFactory);
        HibernateInfoHolder.setServiceRegistry(serviceRegistry);
    }

    @Override
    public void disintegrate(SessionFactoryImplementor sessionFactory, SessionFactoryServiceRegistry serviceRegistry) {
    }
}

使用它

    new SchemaExport((MetadataImplementor) HibernateInfoHolder.getMetadata()).create(true, true);
    new SchemaUpdate(HibernateInfoHolder.getServiceRegistry(), (MetadataImplementor) HibernateInfoHolder.getMetadata()).execute(true, true);

您可以在此处找到其他信息Programmatic SchemaExport / SchemaUpdate with Hibernate 5 and Spring 4

Java Persistence API有Configuration over Convention原则，但Validation API仅用于验证目的。验证不是绝对的，您可以在同一个字段上放置不同的验证规则。

如果你有例如

@Size(max = 50)
@NotNull(groups = DefaultGroup.class)
@Null(groups = SecondGroup.class)
private String shortTitle;

然后它被解释为

@Size(max = 50)
@NotNull(groups = DefaultGroup.class)
@Null(groups = SecondGroup.class)
@Column(length = 255, nullable = true)
private String shortTitle;

在此处查看更多详情 Why does Hibernate Tools hbm2ddl generation not take into account Bean Validation annotations?

Answer 2

对于Hibernate 5.2.7（在我的例子中）我已经写了一个方法来导出基于包扫描的模式，如：

static void exportSchema(
        DataSource dataSource,
        Class<? extends Dialect> dialect,
        String... packagesToScan) {

    StandardServiceRegistryBuilder registryBuilder = new StandardServiceRegistryBuilder()
            .applySetting(DATASOURCE, dataSource)
            .applySetting(DIALECT, dialect); // dialect could be omitted
    MetadataSources metadataSources = new MetadataSources(registryBuilder.build());

    PathMatchingResourcePatternResolver resourceLoader = new PathMatchingResourcePatternResolver();
    new LocalSessionFactoryBuilder(null, resourceLoader, metadataSources)
            .scanPackages(packagesToScan);

    Metadata metadata = metadataSources.buildMetadata();

    new SchemaExport()
            .setFormat(true)
            .create(EnumSet.of(STDOUT, DATABASE), metadata);
}

hibernate 5和spring - 使用SchemaExport生成ddl

2 个答案: