我有一个对象,比如Response.java,如下所示:
class Response
{
private User user; // has firstName, lastName, age etc.
private Address address; // has city, state, country etc.
private OrderInfo orderInfo; // has orderNumber, orderDate etc.
// constuctors, getters/setters follow
}
我需要将这些对象的List转换为csv,所以我的最终目标是:
firstName, lastName, age, city, state, country, latitude, orderNumber, orderDate
john, doe, 25, dallas, tx, usa, somelat, 101, 08/17/2015
jane, doe, 21, atlant, ga, usa, somelat, 102, 08/15/2015
我试图使用两个库 - jackson(csv dataformat),org.json(JsonArray),但我无法获得所需的结果。
这是我的jackson csv代码:
Response response = getResponse();
final CsvMapper mapper = new CsvMapper();
final CsvSchema schema = mapper.schemaFor(Response.class);
final String csv = mapper.writer(schema).writeValueAsString(response);
杰克逊,我正在接受
com.fasterxml.jackson.core.JsonGenerationException: CSV generator does not support Object values for properties
有没有办法按照我需要的方式将复合对象转换为csv(只是没有像分组一样的json的字段)?
答案 0 :(得分:6)
所以我运行了你在测试项目中使用的类似代码,看起来你需要在所有对象(User,Address和OrderInfo)上使用@JsonUnwrapped。
杰克逊CSV不支持将对象作为属性,这就是您获得该异常的原因。以下是Github上的问题:Jackson CSV Object properties issue
以下是我用来验证这一点的示例代码:
Test response = new Test();
response.setNum(1);
Stub s = new Stub();
s.setAge("12");
s.setName("Colin");
response.setS(s);
final CsvMapper mapper = new CsvMapper();
final CsvSchema schema = mapper.schemaFor(Test.class);
final String csv = mapper.writer(schema.withUseHeader(true)).writeValueAsString(response);
System.out.println(csv);
以上代码的输出如下:
num,age,name
1,12,Colin