我在PHP中使用Parse
REST API
,并且正在努力弄清楚如何做两件事。
发送给频道的所有用户:
{
"data": {
"alert": "This is a test!!",
"sound": "default",
"badge": 1
},
"where": {
"channels": [
"puc"
]}
}
}
发送JSON会给我错误:
{"code":102,"error":"equality needs a value instead of [puc] "}
发送到特定设备令牌/令牌:
{
"data": {
"alert": "This is a test!!",
"sound": "default",
"badge": 1
},
"where": {
"channels": [
"puc"
],
"deviceToken": {
"$in": [
"DSFSAFJDSLKWRJKLJGLKASGLK"
]
}
}
}
发送JSON会给我错误:
{"code":102,"error":"equality needs a value instead of [puc] "}
我做错了什么?有人能指出我这两次推进的正确方向吗?
答案 0 :(得分:1)
在channels
子句中使用where
时,它只需要一个值,而不是一个数组:
发送给频道的所有用户:
{
"data": {
"alert": "This is a test!!",
"sound": "default",
"badge": 1
},
"where": {
"channels": "puc"
}
}
}
发送到特定设备令牌/令牌:
{
"data": {
"alert": "This is a test!!",
"sound": "default",
"badge": 1
},
"where": {
"channels": "puc",
"deviceToken": {
"$in": [
"DSFSAFJDSLKWRJKLJGLKASGLK"
]
}
}
}
如果您需要传递数组,则必须像使用" deviceToken"那样使用$in
。
或者,当您没有除频道之外的任何其他标准时,您不需要放置where子句:
{
"data": {
"alert": "This is a test!!",
"sound": "default",
"badge": 1
},
"channels": [
"puc"
]
}
您可以在文档中找到更多示例和信息:https://parse.com/docs/rest/guide/#push-notifications-sending-pushes