请使用以下代码:
<div id="work">
<div class="large-{{columns}} large-offset-{{columns}} columns projects">
</div>
</div>
我们的想法是<div class="large-{{columns}} large-offset-{{columns}} columns projects">
可以在#work
内无限期生成{{columns}}
,而{{columns}}
会生成0到12之间的数字。
我想要做的是运行一些JavaScript,它通过<div id="work">
<div class="row">
<div class="large-8 large-offset-4 columns projects"></div>
</div>
<div class="row">
<div class="large-6 large-offset-0 columns projects></div>
<div class="large-6 large-offset-0 columns projects"></div>
</div>
<div class="row">
<div class="large-4 large-offset-0 columns projects"></div>
<div class="large-8 large-offset-0 columns projects"></div>
</div>
<div class="row">
<div class="large-12 large-offset-0 columns projects"></div>
</div>
</div>
生成的数字,每次总和即将超过12时,相关的div被包含在一个新的div中,类为#34;行&#34;
生成的HTML可能如下所示:
var currentItem = 0;
function rotate() {
container.stop()
.animate({
'left': item_width * -1 * currentItem
}, 1500);
currentItem++;
if (currentItem >= 5) {
currentItem = 0;
}
}
我该如何做到这一点?
答案 0 :(得分:2)
您可以使用以下正则表达式从每个div的类名中提取{{columns}}
值:
/large-(\d+)\s* large-offset-(\d+)/
这会计算应添加到运行总和的增量:
var matches = /large-(\d+)\s* large-offset-(\d+)/.exec(item.className),
delta = parseInt(matches[1], 10) + parseInt(matches[2], 10);
您可以使用document.createElement
创建新的行div,并使用原始div的克隆填充它们。
演示:
function makeRowDiv(buildRow) {
var row = document.createElement('div');
row.className = 'row';
for (var i = 0; i < buildRow.length; ++i) {
row.appendChild(buildRow[i]);
}
return row;
}
window.onload = function () {
var work = document.getElementById('work'),
items = work.getElementsByTagName('div'),
newWork = document.createElement('div');
var buildRow = [],
count = 0;
for (var i = 0; i < items.length; ++i) {
var item = items[i];
if (item.className.indexOf('columns') == -1) {
continue;
}
// Extract the desired value.
var matches = /large-(\d+)\s* large-offset-(\d+)/.exec(item.className),
delta = parseInt(matches[1], 10) + parseInt(matches[2], 10);
if (count + delta > 12 && buildRow.length != 0) {
newWork.appendChild(makeRowDiv(buildRow));
count = 0;
buildRow = [];
}
buildRow.push(item.cloneNode(true));
count += delta;
}
if (buildRow.length != 0) {
newWork.appendChild(makeRowDiv(buildRow));
}
// Replace work with newWork.
work.parentNode.insertBefore(newWork, work);
work.parentNode.removeChild(work);
newWork.id = 'work';
};
body {
font-family: sans-serif;
font-size: 14px;
color: #444;
}
#work .row {
padding: 1px;
margin: 8px;
background: #deedff;
border: 1px solid #c4d1e1;
}
#work .row div {
/* display: inline; */
padding: 1px 4px 2px 4px;
margin: 4px;
background: #fff3fc;
border: 1px solid #ded3dc;
}
#work .row div div {
/* display: inline; */
padding: 1px 4px 2px 4px;
margin: 4px;
background: #eee;
border: 1px solid #ddd;
}
p {
padding: 0;
margin: 0;
}
<div id="work">
<div class="large-8 large-offset-4 columns projects">
<div class="child-div"><p>8</p></div>
<div class="child-div"><p>4</p></div>
</div>
<div class="large-6 large-offset-0 columns projects">
<div class="child-div"><p>6</p></div>
</div>
<div class="large-3 large-offset-3 columns projects">
<div class="child-div"><p>3</p></div>
<div class="child-div"><p>3</p></div>
</div>
<div class="large-4 large-offset-0 columns projects">
<div class="child-div"><p>4</p></div>
</div>
<div class="large-8 large-offset-0 columns projects">
<div class="child-div"><p>8</p></div>
</div>
<div class="large-6 large-offset-6 columns projects">
<div class="child-div"><p>6</p></div>
<div class="child-div"><p>6</p></div>
</div>
</div>
如果你有足够的水平空间,你可以取消注释CSS行/* display: inline; */
,看看每个行div的子项并排排列。
答案 1 :(得分:0)
我会使用split
或replace
来获取整数并按照建议here进行总结。
示例:
var str = 'large-8 large-offset-6';
var large = str.replace(/.*large-(\d+)/, '$1');
var offset = str.replace(/.*large-offset-(\d+)/, '$1');
然后使用this等解决方案来获取包装器。
示例:
var divs = $("#work > .columns");
var count = <count how many cols are need to reach sum>
for(var i = 0; i < divs.length; i+=count) {
divs.slice(i, i+count).wrapAll("<div class='new'></div>");
}
我确定你可以清理它并完成它但是应该给你一个想法。我今晚有空的时候会完成。