这是html文件。
public class MyClass { ... }
public partial class MyForm : Form { ... }
test2.php文件
<html>
<head>
<script>
function showUser(str) {
if (str == "") {
return;
} else {
if (window.XMLHttpRequest) {
// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp = new XMLHttpRequest();
} else {
// code for IE6, IE5
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function() {
if (xmlhttp.readyState == 4 && xmlhttp.status == 200)
{
var doc = window.document.createElement("doc");
var a = JSON.parse(xmlhttp.responseText);
document.getElementById("stuname").value=a.first;
document.getElementById("branch").value=a.second;
document.getElementById("year").value=a.third;
document.getElementById("category").value=a.four;
}
}
xmlhttp.open("GET","test2.php?q="+str,true);
xmlhttp.send();
}
}
</script>
</head>
<body>
<form>
Roll Number:<br>
<input type="text" name="rollno" id="rollno" onblur="showUser(this.value)">
<br>
Student Name:<br>
<input type="text" name="stuname" id="stuname" value="">
Branch:<br>
<input type="text" name="branch" id="branch" value="">
Year:<br>
<input type="text" name="year" id="year" value="">
Category:<br>
<input type="text" name="category" id="category" value="">
</form>
<br>
</body>
</html>
我无法将值加载到出错的文本框中。即使我已经看到stackoverflow但我无法得到它。当我通过将rollno值传递给q键入test2.php它将显示数据,但是当我从html传递一个值时,它无法将值设置为文本框字段。
答案 0 :(得分:1)
从test2.php中删除所有html标记。 ajax文档不需要任何html标记。
答案 1 :(得分:0)
Hi this one will be helpful to you .
<html>
<head>
</head>
<body>
<input type="button" onclick="showUser('ok');" value="click to ru me" />
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script>
function showUser(str)
{
if (str=="")
{
return;
}
else
{
if (window.XMLHttpRequest) { xmlhttp = new XMLHttpRequest(); }
else { xmlhttp = new ActiveXObject("Microsoft.XMLHTTP"); }
xmlhttp.onreadystatechange = function()
{
if (xmlhttp.readyState == 4 && xmlhttp.status == 200)
{
//var doc = window.document.createElement("doc");
var parsed = JSON.parse(xmlhttp.responseText);
for(var x in parsed)
{
var First=parsed[x].first;
var Second=parsed[x].second;
var Third=parsed[x].third;
var Fourth=parsed[x].fourth;
console.log("first="+First+" second="+Second+" third="+Third+" fourth="+Fourth);
document.getElementById("stuname").value=parsed[x].first;
document.getElementById("branch").value=parsed[x].second;
document.getElementById("year").value=parsed[x].third;
document.getElementById("category").value=parsed[x].fourth;
}
}
}
xmlhttp.open("GET","phpex.php?q="+str,true);
xmlhttp.send();
}
}
</script>
<input type="text" id="stuname" />
<input type="text" id="branch" />
<input type="text" id="year" />
<input type="text" id="category" />
</body>
</html>
Ajax File Name phpex.php . ajax page code is below
<?php
echo '[{"first":"1111","second":"2222","third":"3333","fourth":"4444"}]';
?>