Question

我有一个xml文档，我必须删除基于的重复<itemGrp> <rateclass>值。

如果有多个<itemGrp>具有相同的<rateclass>，则排除除1 <itemGrp>以外的所有内容

包括xml和xslt，结果可以在http://www.freeformatter.com/xsl-transformer.html

看到

通过粘贴xml和xslt

XSLT：

<xsl:stylesheet version="2.0"
    xmlns:a="http://xml.amadeus.com/FQDRES_12_1_1A"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:xsd="http://www.w3.org/2001/XMLSchema"
    xmlns:msxsl="urn:schemas-microsoft-com:xslt"
    xmlns:vbs="urn:schemas-sqlxml-org:vbs">
    <!-- Main Template -->
    <xsl:template match="/Responses">
        <xsl:element name="Fares">
            <xsl:for-each select="./RequestResponse/Fare_DisplayFaresForCityPairReply">
                <xsl:for-each select="./a:flightDetails">

                    <!-- inside each flight details, we want to get all of the item groups-->
                    <xsl:for-each select="./a:itemGrp">
                        <!-- if rateclass repeating then skip this record other wise add this record to output file-->
                        <xsl:element name="Calss">
                            <xsl:value-of select="./a:fareQualifItem/a:additionalFareDetails/a:rateClass"/>
                        </xsl:element>                           
                    </xsl:for-each>
                </xsl:for-each>
            </xsl:for-each>
        </xsl:element>
    </xsl:template>
</xsl:stylesheet>

XML：

   <Responses>
      <RequestResponse>    
        <Fare_DisplayFaresForCityPairReply xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
     <flightDetails xmlns="http://xml.amadeus.com/FQDRES_12_1_1A">
            <itemGrp>
              <fareQualifItem>
                <additionalFareDetails>
                  <rateClass>XK2DCA</rateClass>
                </additionalFareDetails>
                <discountDetails>
                  <fareQualifier>725</fareQualifier>
                </discountDetails>
              </fareQualifItem>
            </itemGrp>
           <itemGrp>
              <fareQualifItem>
                <additionalFareDetails>
                  <rateClass>XK2DCAB</rateClass>
                </additionalFareDetails>
                <discountDetails>
                  <fareQualifier>725</fareQualifier>
                </discountDetails>
              </fareQualifItem>
            </itemGrp>
            <itemGrp>
              <fareQualifItem>
                <additionalFareDetails>
                  <rateClass>XK2DCA</rateClass>
                </additionalFareDetails>
                <discountDetails>
                  <fareQualifier>725</fareQualifier>
                </discountDetails>
              </fareQualifItem>
            </itemGrp>
    </flightDetails>
     <flightDetails xmlns="http://xml.amadeus.com/FQDRES_12_1_1A">
         <itemGrp>
              <fareQualifItem>
                <additionalFareDetails>
                  <rateClass>AAXK2DCA</rateClass>
                </additionalFareDetails>
                <discountDetails>
                  <fareQualifier>725</fareQualifier>
                </discountDetails>
              </fareQualifItem>
            </itemGrp>
           <itemGrp>
              <fareQualifItem>
                <additionalFareDetails>
                  <rateClass>BXK2DCAB</rateClass>
                </additionalFareDetails>
                <discountDetails>
                  <fareQualifier>725</fareQualifier>
                </discountDetails>
              </fareQualifItem>
            </itemGrp>
            <itemGrp>
              <fareQualifItem>
                <additionalFareDetails>
                  <rateClass>AAXK2DCA</rateClass>
                </additionalFareDetails>
                <discountDetails>
                  <fareQualifier>725</fareQualifier>
                </discountDetails>
              </fareQualifItem>
            </itemGrp>               
    </flightDetails>
    </Fare_DisplayFaresForCityPairReply>
  </RequestResponse>
</Responses>

回复是：

  <?xml version="1.0" encoding="UTF-8"?>
<Fares>
   <Calss>XK2DCA</Calss>
   <Calss>XK2DCAB</Calss>
   <Calss>XK2DCA</Calss>
   <Calss>AAXK2DCA</Calss>
   <Calss>BXK2DCAB</Calss>
   <Calss>AAXK2DCA</Calss>
</Fares>

我想要的是：

 <?xml version="1.0" encoding="UTF-8"?>
<Fares>
   <Calss>XK2DCA</Calss>
   <Calss>XK2DCAB</Calss>   
   <Calss>AAXK2DCA</Calss>
   <Calss>BXK2DCAB</Calss>   
</Fares>

谢谢Michael的回答。可能已经解决了：

XSLT 1.0

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:a="http://xml.amadeus.com/FQDRES_12_1_1A" xmlns:msxsl="urn:schemas-microsoft-com:xslt" xmlns:vbs="urn:schemas-sqlxml-org:vbs" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" version="1.0">
   <!-- Main Template -->
   <xsl:key name="rateClass" match="/Responses/RequestResponse/Fare_DisplayFaresForCityPairReply/a:flightDetails/a:itemGrp/a:fareQualifItem/a:additionalFareDetails/a:rateClass/text()" use="." />
   <xsl:template match="/Responses">
      <xsl:element name="Fares">
         <xsl:for-each select="./RequestResponse/Fare_DisplayFaresForCityPairReply">
            <xsl:for-each select="./a:flightDetails">
               <!-- inside each flight details, we want to get all of the item groups-->
               <xsl:for-each select="./a:itemGrp">
                  <!-- if rateclass repeating then skip this record other wise add this record to output file-->
                  <xsl:variable name="ItemGroup_Items" select="." />
                  <!--<xsl:variable name="rateClass_1" select="./a:fareQualifItem/a:additionalFareDetails/a:rateClass"/>
                <xsl:if test="vbs:CheckExists($rateClass_1) = 'FALSE'">-->
                  <xsl:for-each select="./a:fareQualifItem/a:additionalFareDetails/a:rateClass/text()[generate-id()= generate-id(key('rateClass',.)[1])]">
                     <xsl:element name="Calss">
                        <xsl:value-of select="." />
                     </xsl:element>
                      <xsl:element name="Value_from_itemGrp">
                        <xsl:value-of select="($ItemGroup_Items/a:fareQualifItem/a:additionalFareDetails/a:rateClass)"/>
                      </xsl:element>
                  </xsl:for-each>
               </xsl:for-each>
            </xsl:for-each>
         </xsl:for-each>
      </xsl:element>
   </xsl:template>
</xsl:stylesheet>

Answer 1

鉴于您最新的XML输入，可以通过以下方式非常简单地实现预期输出：

XSLT 2.0

<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:a="http://xml.amadeus.com/FQDRES_12_1_1A"
exclude-result-prefixes="a">
<xsl:output method="xml" version="1.0" encoding="utf-8" indent="yes"/>

<xsl:template match="/Responses">
    <Fares>
        <xsl:for-each select="distinct-values(RequestResponse/Fare_DisplayFaresForCityPairReply/a:flightDetails/a:itemGrp/a:fareQualifItem/a:additionalFareDetails/a:rateClass)">
            <Calss>
                <xsl:value-of select="."/>
            </Calss>
        </xsl:for-each>  
    </Fares>
</xsl:template>

</xsl:stylesheet>

显示不同的记录，使用xslt从xml文档中删除重复项

1 个答案: