Question

拥有主方法及其中的所有逻辑。如何在JUnit中测试（模拟）input.txt？我应该将代码分成较小的部分，以便我可以通过方法调用它吗？文件输入应如下所示

/* 
   input.txt 
   add 2 
   add 2 
   apply 3 
   correct result 3 + 2 + 2 = 7
*/

public class Main {
    public static void main(String[] args) {
        List<Operation> listOperations = new ArrayList<Operation>();
        int size = listOperations.size() - 1;
        int keepingCount = 0;

        try {
            File file = new File("input.txt");
            Scanner input = new Scanner(file);

            while (input.hasNextLine()) {
                String line = input.nextLine();
                String[] parts = line.split(" ");
                String operationSign = parts[0];
                int numberFromLine = Integer.parseInt(parts[1]);
                Operation operation = new Operation();
                operation.setCalculation(operationSign);
                operation.setNumber(numberFromLine);

                if (!operation.getCalculation().equals("apply")) {
                    listOperations.add(operation);
                } else {
                    listOperations.add(operation);
                    break;
                }
            }
            input.close();

            for (int x = 0; x < size; x++) {
                if (listOperations.get(x).calculation.equals("add")) {
                    if (keepingCount == 0) {
                        keepingCount = listOperations.get(x).number + listOperations.get(size).number;
                    } else {
                        keepingCount = listOperations.get(x).number + keepingCount;
                    }
                }
                if (listOperations.get(x).calculation.equals("multiply")) {
                    if (keepingCount == 0) {
                        keepingCount = listOperations.get(x).number * listOperations.get(size).number;
                    } else {
                        keepingCount = listOperations.get(x).number * keepingCount;
                    }
                }
                if (listOperations.get(x).calculation.equals("substract")) {
                    if (keepingCount == 0) {
                        keepingCount = listOperations.get(x).number - listOperations.get(size).number;
                    } else {
                        keepingCount = keepingCount - listOperations.get(x).number;
                    }
                }
                if (listOperations.get(x).calculation.equals("divide")) {
                    if (keepingCount == 0) {
                        keepingCount = listOperations.get(size).number / listOperations.get(x).number;
                    } else {
                        keepingCount = keepingCount / listOperations.get(x).number;
                    }
                }
            }
            System.out.println(keepingCount);
        } catch (Exception ex) {
            ex.printStackTrace();
        }
    }

Answer 1

整个逻辑在您的主要测试中，这更像是系统测试（集成测试），最好的方法是为每个方法编写单元测试，最后您可以测试main以确保所有方法都正常工作很好。

来自Stanford University Lecture Notes：

“单元测试：专注，低级; 测试个别方法或方法。更容易确保每段代码都经过测试更容易编写和运行可能无法捕获来自不同代码段之间的交互的问题系统测试（或集成测试）：测试整个系统一起工作。有利于确保所有部分协同工作可以在片段之间产生更复杂的交互写作和运行更难。“

单元测试单片主方法

1 个答案: