Question

我正在使用Codeigniter，并尝试将一个查询的结果传递给第二个。我收到错误

＆＃34;致命错误：无法使用CI_DB_mysql_result类型的对象作为数组＆＃34;。

任何建议将不胜感激。对于我的$ truck_num查询，我只是在一个名为truck_num的字段中获取卡车列表。然后我试图将这些结果传递给进行一些计算的查询。

控制器 ///////////

    function average_battery_life_by_truck() {

    $truck_num = $this->mhedash_model->select_truck();

    foreach($truck_num->result_array() as $row) {
    $array = $row['truck_num']; 
    $results[] = $this->mhedash_model->select_battery_life_truck($array);

    }

    $data['array'] = $results;

    $data['main_content'] = 'mhe/average_truck_bat';
    return $this->load->view('includes/template',$data);



}

查看 //////

<?php error_reporting (E_ALL ^ E_NOTICE); ?>

<p><h1></h1></p>


<FORM 
<></div>
<br />
<p><h4 id="date"></h4></p>
<h3></h3>
<table id="table" class="sortable">
<THEAD>
    <TR>
        <TH>Truck</TH>
        <TH>Average Hours</TH>

    </TR>
</THEAD>

<TBODY>
    <?php $count = 0; ?>
<?php foreach($array as $row): ?>

    <TR >
        <TD><?php echo $row['average_bat_life']; ?></TD>
        <TD><?php echo $row['truck_num']; ?></TD>

    </TR>
    <?php $count++; ?>

<?php endforeach;?>
</TBODY>

</table>

MODEL /////

    function select_truck() {
    mysql_select_db('battery');
    $this->table_name = 'truck';


    $truck_num = "SELECT 
                    truck_num
                  FROM 
                    truck
                  WHERE 
                    battery_type_id = '5'
                    or battery_type_id = '8'
                    or battery_type_id = '10'
                    or battery_type_id = '9'
                  ORDER BY truck_num
              ";

             return $this->db->query($truck_num);
}

function select_battery_life_truck($data) {
    mysql_select_db('battery');
    $this->table_name = 'truck_hours';
    $truck_num = $this->db->escape($data);


    /*This query takes the current row's metered hours and subtracts it with the previous row's metered hours.
    We then average out the time the battery was on the truck for the date range */


    $query = "SELECT 
                ROUND(AVG(metered_hours-b),2) average_bat_life,
                truck_num
              FROM   (SELECT
                        id,
                        metered_hours,
                        loc_id,
                            (SELECT MAX(metered_hours) 
                             FROM 
                                (SELECT @rownum:=@rownum+1 id, truck_hours.metered_hours,truck_hours.loc_id from truck_hours,truck, (SELECT @rownum:=0) r where truck_hours.loc_id = truck.loc_id and truck.truck_num = $truck_num and DATE_SUB(CURDATE(),INTERVAL 30 DAY) >= truck_hours.ctrl_date  ) a 
                                 WHERE a.metered_hours < t.metered_hours)b

                                 FROM 
                            (SELECT @rownum:=@rownum+1 id, truck_hours.metered_hours,truck_hours.loc_id from truck_hours,truck, (SELECT @rownum:=0) r where truck_hours.loc_id = truck.loc_id and truck.truck_num = $truck_num and DATE_SUB(CURDATE(),INTERVAL 30 DAY) >= truck_hours.ctrl_date ) AS t) c,
                            truck

              WHERE c.loc_id = truck.loc_id 
              ORDER BY average_bat_life";
    return $this->db->query($query);
}

Answer 1

在第二个查询中，您无法从数据库中获取数据。

所以你需要添加fetch方法

在您的控制器中

foreach($truck_num->result_array() as $row) {
    $array = $row['truck_num']; 
    $result = $this->mhedash_model->select_battery_life_truck($array);
    foreach($result->result_array() as $row_data) {
         $results[] = $row_data; 
    }
    }
      $data['array'] = $results;
      $data['main_content'] = 'mhe/average_truck_bat';
      $this->load->view('includes/template',$data);

如何将一个查询的结果传递给第二个查询并将结果显示在一个表中？

1 个答案: