Question

我在Android的eclipse中制作天气应用程序，我需要在1天之间显示描述天气的图标，间隔3小时。

我从http://api.openweathermap.org/data/2.5/forecast?q=Melbourne

获取API

然后我使用http://www.jsonschema2pojo.org/在java类中创建（我认为这就是它的作用..）

现在我收到了以下代码：

private class ForecastForHoursTask extends AsyncTask<String, Integer, String> {

    String measurement = checkMeasurement();

    private final String SERVICE_ADDRESS_START = "http://api.openweathermap.org/data/2.5/forecast?q=";

    ProgressBar progressBar;

    public ForecastForHoursTask(ProgressBar progressBar) {
        this.progressBar = progressBar;
        progressBar.setProgress(0);
    }

    @Override
    protected void onPreExecute() {
        progressBar.setVisibility(View.VISIBLE);
    }

    @Override
    protected String doInBackground(String... params) {
        String serviceAddress = SERVICE_ADDRESS_START + params[0];
        StringBuilder response = new StringBuilder();
        DefaultHttpClient client = new DefaultHttpClient();
        HttpGet httpGet = new HttpGet(serviceAddress);
        try {
            HttpResponse execute = client.execute(httpGet);
            InputStream content = execute.getEntity().getContent();
            BufferedReader buffer = new BufferedReader(new InputStreamReader(content));
            String bufferString = "";
            while ((bufferString = buffer.readLine()) != null) {
                response.append(bufferString);
            }
        } catch (Exception e) {
            e.printStackTrace();
        }
        return response.toString();

    }

    @Override
    protected void onProgressUpdate(Integer... progress) {
        super.onProgressUpdate(progress);
        if (this.progressBar != null) {
            progressBar.setProgress(progress[0]);
        }
    }

    @Override
    protected void onPostExecute(String result) {
        ImageView imgFirst = (ImageView) findViewById(R.id.imgEightAm);
        ImageView imgSecond = (ImageView) findViewById(R.id.imgElevenAm);
        ImageView imgThird = (ImageView) findViewById(R.id.imgTwoPm);
        ImageView imgFourth = (ImageView) findViewById(R.id.imgFivePm);
        ImageView imgFifth = (ImageView) findViewById(R.id.imgEightPm);
        ImageView imgSixth = (ImageView) findViewById(R.id.imgElevenPm);
        ImageView imgSeventh = (ImageView) findViewById(R.id.imgTwoAm);
        ImageView imgEighth = (ImageView) findViewById(R.id.imgFiveAm);
        TextView imgTest = (TextView) findViewById(R.id.lblTest);

        Gson gson = new Gson();
        NewRoot newitem = gson.fromJson(result, NewRoot.class);

        progressBar.setProgress(0);
        progressBar.setVisibility(-1);
    }
}

我想要将图标设置为ImageView。但我很难在onPostExecute中做些什么。我想我需要对数据进行排序，以便我可以搜索（dt_txt）字段并获取相关的（图标）值，这样我就可以通过（icon）值将ImageView设置为相应的图像。我坚持要怎么做。

Answer 1

这可能是序列化问题。 NewRoot类中的名称和数据类型必须与从API下载的名称和数据类型相匹配。如果需要，您也可以使用Gson注释设置它们。这是一本很棒的指南，你应该阅读：link。

不知道如何处理JSON数据

1 个答案: