Question

我正在研究Django框架。现在，我正在为下面的用户注册创建一个类。我在第6行遇到错误。你能帮忙吗？

1: class JoinForm(forms.Form):
2:    MONTH = {
3:        1:('Jan'), 2:('Feb'), 3:('March'), 4:('Apl'), 5:('May'), 6:('Jun'),
4:        7:('July'), 8:('Aug'), 9:('Sep'), 10:('Oct'), 11:('Nov'), 12:('Dec')
5:    }
6:    YEAR = self.makeYearChoice(self,1940)
7:    email = forms.EmailField(label='Email Address', max_length=50)
8:    name = forms.CharField(label='Real Name', max_length=20)
9:    birth = forms.DateField(label='Birth Date', widget=SelectDateWidget(years=YEAR, months=MONTH))
10:   loc = forms.CharField(label='Resident Location', max_length=40)
11:   passwd = forms.CharField(label='Password', max_length=16, widget=forms.PasswordInput)

12:   def makeYearChoice(self,startYear):
13:       YEARS = ();
14:       thisYear = datetime.now().year
15:       for year in range(startYear,thisYear):
16:           YEARS.append(year)
17:       return YEARS

Answer 1

这与Django无关;类定义的主体有自己的命名空间，并按写入的顺序运行，所以此时：

class JoinForm(forms.Form):
    ...
    YEAR = self.makeYearChoice(self,1940)  # here
    ...

不仅self未定义， makeYearChoice也不是！您可以通过以下两种方式解决此问题之一：

移动方法定义上面类属性的设置，并直接调用

class JoinForm(forms.Form):
    ...
    def makeYearChoice(self, startYear):  # define the method first
        ...

    YEAR = makeYearChoice(None,1940)  # don't have an instance, but who cares?
    ...

一旦定义了类，就会给你一个冗余的实例方法;或

将它作为一个独立的函数，只需在类中调用它：

def makeYearChoice(startYear):
    ...

class JoinForm(forms.Form):
    ...
    YEAR = makeYearChoice(1940)  # no fuss about self argument
    ...

我强烈赞成后者。另外，你应该阅读the style guide;方法和属性名称通常为lowercase_with_underscores，逗号后应该有空格。

Django View Class：name＆＃39; self＆＃39;没有定义

1 个答案: