问题1 - 任何人都可以告诉我代码有什么问题吗?我有一个脚本只获取pdf文件....
问题2 - 有没有办法在另一个像这样的php文件中获取用户名和密码;
define("Email", "xxxxx.com");
define("Password", "******");
我该怎么办?请更喜欢以下代码。
<?php
$hostname = '{imap.gmail.com:993/imap/ssl}INBOX';
$username = 'xxxxx@gmail.com';
$password = '*******';
$savedirpath = "/Attachment";
$type = 'ReadAttachment';
$obj = new $type;
$obj->getdata($hostname ,$username ,$password,$savedirpath);
class ReadAttachment
{
function getdecodevalue($message,$coding) {
switch($coding) {
case 0:
case 1:
$message = imap_8bit($message);
break;
case 2:
$message = imap_binary($message);
break;
case 3:
case 5:
$message=imap_base64($message);
break;
case 4:
$message = imap_qprint($message);
break;
}
return $message;
}
function getdata($hostname ,$username ,$password,$savedirpath) {
$savedirpath = str_replace('\\', '/', $savedirpath);
if (substr($savedirpath, strlen($savedirpath) - 1) != '/') {
$savedirpath .= '/';
}
$mbox = imap_open ($hostname , $username , $password) or die("can't connect: " . imap_last_error());
$message = array();
$message["attachment"]["type"][0] = "text";
$message["attachment"]["type"][1] = "multipart";
$message["attachment"]["type"][2] = "message";
$message["attachment"]["type"][3] = "application";
$message["attachment"]["type"][4] = "audio";
$message["attachment"]["type"][5] = "image";
$message["attachment"]["type"][6] = "video";
$message["attachment"]["type"][7] = "other";
$MC = imap_check($mbox);
$result = imap_fetch_overview($mbox,"1:{$MC->Nmsgs}",0);
$jk = 1;
foreach ($result as $overview) {
$subj = $overview->subject;
$date= strtotime($overview->date);
$unixDate = date("YmdHis", $date);
$email= $overview->from;
$opening = strpos($email, '<')+1; // removed username of a sender
$closing = strpos($email, '>'); // removed username of a sender
$from = substr($email, $opening, $closing-$opening);
$structure = imap_fetchstructure($mbox, $jk); //, FT_UID - for pop3
$parts = (isset($structure->parts) ? $structure->parts : false);
$fpos=2;
for($i = 1; $i < count($parts); $i++) {
$message["pid"][$i] = ($i);
$part = $parts[$i];
if($part->disposition == "ATTACHMENT") {
$message["type"][$i] = $message["attachment"]["type"][$part->type] . "/" . strtolower($part->subtype);
$message["subtype"][$i] = strtolower($part->subtype);
$ext=$part->subtype;
$params = $part->dparameters;
$filename=$part->dparameters[0]->value;
$mege="";
$data="";
$mege = imap_fetchbody($mbox,$jk,$fpos);
$filename="$filename";
$extension=pathinfo($filename);
$file_extension = $extension['extension'];
if($file_extension === "pdf")
{
$new_filename = $subject . "*" . $from . "*" . "$unixDate" . ".pdf";
$fp=fopen($savedirpath.$new_filename,'w');
$data=$this->getdecodevalue($mege,$part->type);
fputs($fp,$data);
fclose($fp);
$fpos+=1;
}
}
} imap_delete($mbox,$jk);
$jk++;
}
imap_expunge($mbox);
imap_errors();
imap_close($mbox);
}
}
?>
答案 0 :(得分:0)
看看这一行:
if ($part->disposition == "ATTACHMENT") {
根据您提供的PHP通知的详细信息,$part
是stdClass
的实例。但是,同样基于您的PHP Notice消息,它没有disposition
属性。
将此行更改为:
if (isset($part->disposition) && $part->disposition == "ATTACHMENT") {
在调用之前确保属性存在。或者,您可以使用property_exists()
; e.g:
property_exists($part, 'disposition');
此外,您可能需要考虑在某处添加条件,以确保$part
实际上是is_object()
的对象:
is_object($part); // `true` if `$part` is any object
或者,具有instanceof
的特定实例类型:
$part instanceof stdClass; // `true` if `$part` is a `stdClass` instance
关于你的第二个问题:如果你有两个单独的问题,你应该创建两个单独的问题。但是,如果您在单独的.php文件中定义任何值并希望将它们包含在当前脚本中,则可以使用require_once
来有效地导入它们; e.g:
<?php
require_once __DIR__ . '/constants.php';
echo FOO;
希望这会有所帮助:)