我可以看到它们与我创建字符串的字节不同! 我用“AES / CBC / PKCS5Padding”来获取字符串。
public static void main(String[] args) {
try {
int randomNumber = CNStationQueueUtil.randInt(0, 99999);
String key = "AES_KEY_TAKENUMB";
byte[] bytes = EncryptHelper.encrypt(key, String.format("%%%d%%%d", 1001, randomNumber));
String str = new String(bytes, "UTF8");
System.out.println("str = " + str);
System.out.println();
byte[] utf8Bytes = str.getBytes("UTF8");
printBytes(utf8Bytes, "utf8Bytes");
} catch (Exception e) {
e.printStackTrace();
}
}
public class EncryptHelper {
public static byte[] encrypt(String key, String value)
throws GeneralSecurityException {
byte[] raw = key.getBytes(Charset.forName("UTF-8"));
if (raw.length != 16) {
throw new IllegalArgumentException("Invalid key size.");
}
SecretKeySpec skeySpec = new SecretKeySpec(raw, "AES");
Cipher cipher = Cipher.getInstance("AES/CBC/PKCS5Padding");
cipher.init(Cipher.ENCRYPT_MODE, skeySpec,
new IvParameterSpec(new byte[16]));
return cipher.doFinal(value.getBytes(Charset.forName("UTF-8")));
}
public static String decrypt(String key, byte[] encrypted)
throws GeneralSecurityException {
byte[] raw = key.getBytes(Charset.forName("UTF-8"));
if (raw.length != 16) {
throw new IllegalArgumentException("Invalid key size.");
}
SecretKeySpec skeySpec = new SecretKeySpec(raw, "AES");
Cipher cipher = Cipher.getInstance("AES/CBC/PKCS5Padding");
cipher.init(Cipher.DECRYPT_MODE, skeySpec,
new IvParameterSpec(new byte[16]));
byte[] original = cipher.doFinal(encrypted);
return new String(original, Charset.forName("UTF-8"));
}
}
答案 0 :(得分:1)
将字符串解码为UTF-8
时,这是因为您将字节编码为UTF-8或兼容的东西。你不能只取byte[]
个随机字节并把它变成一个字符串,因为它是二进制数据而不是文本。
您可以使用Base64编码器作为二进制文件,使用Base64解码器将其转换回原始字节。
执行此操作的一种黑客方法是使用ISO-8859-1
,但这通常是一个坏主意,因为您混淆了二进制文本和文本数据。