Question

有人可以修改我的查询，我无法让它工作。

UPDATE `users` SET `steamName`, `steamRealName`, `ip` = VALUE('$steamName', '$steamRealName', '$ip') where `steamID` = '$steamID'

我正在尝试使用我的数据库表中的数据替换用户的Steam名称，实名和IP地址，但仅针对Steam ID = $ steamID的列。

我使用了以下变量：

$steamID = $_SESSION['steamid'];
$steamName = $steamprofile['personaname'];
$steamRealName = $steamprofile['realname'];
if (!empty($_SERVER['HTTP_CLIENT_IP'])) {
    $ip = $_SERVER['HTTP_CLIENT_IP'];
} elseif (!empty($_SERVER['HTTP_X_FORWARDED_FOR'])) {
    $ip = $_SERVER['HTTP_X_FORWARDED_FOR'];
} else {
    $ip = $_SERVER['REMOTE_ADDR'];
};

Answer 1

将您的语句更改为有效的SQL语句：

UPDATE `users` SET `steamName` ='$steamName', `steamRealName` ='$steamRealName', `ip` = '$ip' where `steamID` = '$steamID'

Answer 2

您的查询语法错误。应该是这样的：

UPDATE `users` SET `steamName`='$steamName', `steamRealName`='$steamRealName', `ip` = '$ip' where `steamID` = '$steamID'

语法为：

Update tablename
set col1=val1,
    col2=val2,
    col3=val3
where condition

Answer 3

30 * * * * php ./maintenance/runJobs.php语法应为：

UPDATE

即

UPDATE theTable SET col1 = col1Val, col2 = col2Val WHERE whereCol = whereColVal;

另请注意，UPDATE `users` SET `steamName` = '$steamName', `steamRealName` = '$steamRealName', `ip` = '$ip' where `steamID` = '$steamID';可能会被欺骗。您不希望在查询中使用此非转义。

Answer 4

试试这个：

Navigation.prototype.save = function(form) {

    if(!this.check_completed()) {
        this.handle_percentage();
        this.strip_space(form);
        form[0].getElementsByClassName("gform_save_link")[0].click();
    }
}

Answer 5

您遇到语法问题，请尝试以下方法：

UPDATE `users` SET `steamName` = '$steamName', `steamRealName` ='$steamRealName', `ip` = '$ip' where `steamID` = '$steamID'

Answer 6

试试这个，

    UPDATE `users` 
    SET    `steamName`     = '$steamName', 
           `steamRealName` = '$steamRealName', 
           `ip`            = '$ip' 
    WHERE  `steamID` = '$steamID'

尝试在PDO中使用Prepared语句。

Answer 7

首先尝试这个：

UPDATE `users` 
SET 
    `steamName` = '$steamName', 
    `steamRealName` = '$steamRealName', 
    `ip` = '$ip'
WHERE `steamID` = '$steamID'

但我强烈建议您使用预准备语句（请参阅PDO）以避免SQL注入漏洞。

此外，请勿直接访问$_SERVER，而是清理它：

$ip = filter_input(INPUT_SERVER, 'HTTP_CLIENT_IP', FILTER_SANITIZE_STRING);

Answer 8

请替换代码

UPDATE `users` SET `steamName`, `steamRealName`, `ip` = VALUE('$steamName', '$steamRealName', '$ip') where `steamID` = '$steamID'

进入

UPDATE users SET steamName='".$steamName."', steamRealName='".$steamRealName."', ip='".$ip."' where `steamID` = '$steamID';

PHP MySQL查询问题

8 个答案: