Question

我想编写一个python代码来检查网站是否正常运行，如果我输入一个随机的东西，比如“无论”程序会说：

“该网站无效。请尝试其他网站。”

如果服务器未启动，它将使我能够检查另一个URL，程序会说：

“网站服务器未启动。请尝试其他服务器。”

再次检查另一个网址。我已经尝试了这么久，总是得到一个我不想得到的异常，我想将异常更改为我选择的打印。

到目前为止我得到的是：

import urllib
print ("Which website would you like to check?")
website_url = raw_input("--> ")

#The user will stuck in a loop until a valid website is exist, using the Application protocol
while urllib.urlopen(website_url).getcode() != 200:
    print ("The website does not exist. Which website would you like to check?")
    website_url = raw_input("--> ")

感谢所有帮助者:)

Answer 1

试试这个：

import urllib
print ("Which website would you like to check?")
website_url = raw_input("--> ")
#The user will stuck in a loop until a valid website is exist, using the Application protocol
while True:
    try:
        if urllib.urlopen(website_url).getcode() != 200:
            print ("The website does not exist. Which website would you like to check?")
        else:
            print "site is up"
    except:
        print "Invalid URL given"
website_url = raw_input("--> ")

Answer 2

    import urllib    
    if website_url.split('//')[0] != 'http:' and website_url.split('//')[0] != 'https:':  # Adds http:// to the given URL because it is the only way to check for server response
        website_url = 'http://' + website_url
    while True: #The user will stuck in a loop until a valid website is exist, using the Application protocol
            try:
                if urllib.urlopen(website_url).getcode() != 200:
                    print ("Invalid URL given. Which website would you like to check?")
                    website_url = raw_input("--> ")
                else:
                    print ("The server is up")
                    break
            except:
                print ("Invalid URL given. Which website would you like to check?")
                website_url = raw_input("--> ")

我想检查网站是否正常

2 个答案: