我正在上这样的课程
@XmlRootElement(name = "executionStats")
public class ScriptExecutionStatistics {
private DateTime start;
private DateTime end;
public ScriptExecutionStatistics() { }
public ScriptExecutionStatistics(DateTime start, DateTime end) {
this.start = start;
this.end = end;
}
@XmlAttribute
public DateTime getStart() {
return start;
}
public void setStart(DateTime start) {
this.start = start;
}
@XmlAttribute
public DateTime getEnd() {
return end;
}
public void setEnd(DateTime end) {
this.end = end;
}
}
我想在xml中序列化它,所以它看起来像这样
<scriptExecutionStatistics start="17.08.2015 18:17:00" end="17.08.2015 18:18:00" />
我知道如果我想将joda时间与jaxb绑定,那么将需要一个适配器,但令人困惑的是我没有真正得到它。所以我已经开始了
public class DateTimeAdapter extends XmlAdapter<ScriptExecutionStatistics, DateTime>{
private static DateTimeFormatter dtf = DateTimeFormat.forPattern("yyyy-MM-dd HH:mm:ss");
@Override
public DateTime unmarshal(ScriptExecutionStatistics vt) throws Exception {
throw new UnsupportedOperationException("Not supported yet.");
}
@Override
public ScriptExecutionStatistics marshal(DateTime bt) throws Exception {
ScriptExecutionStatistics stats = new ScriptExecutionStatistics();
}
}
请你帮我完成它。 提前致谢
答案 0 :(得分:4)
DateTimeAdapter
应该DateTime
编组/解组String
,例如public class DateTimeAdapter extends XmlAdapter<String, DateTime>{
private static DateTimeFormatter dtf = DateTimeFormat.forPattern("yyyy-MM-dd HH:mm:ss");
@Override
public DateTime unmarshal(String vt) throws Exception {
return dtf.parseDateTime(vt);
}
@Override
public String marshal(DateTime bt) throws Exception {
return dtf.print(bt);
}
}
。
ScriptExecutionStatistics
另外,您应该使用@XmlJavaTypeAdapter
注释在@XmlJavaTypeAdapter(DateTimeAdapter.class)
@XmlAttribute
public DateTime getStart() {
return start;
}
中注释相应的字段/ getter
(:User)