Question

如何在视图外设置按钮？因此，您可以在屏幕外生成唯一的坐标。我可以将按钮从该位置设置为中间位置。

我有这个代码来生成坐标

var p = CGPoint(x:Int(arc4random()%1000),y:Int(arc4random()%1000))

这是有效的，但我希望获得屏幕外的随机坐标，或者换句话说用户看到的内容。

Answer 1

那样的事情呢？

func generateRandomPointOutsideOfViewBounds (view: UIView) -> CGPoint{
    var min: UInt32 = UInt32(view.frame.size.width)
    var max: UInt32 = UInt32(1000)
    let randomX: UInt32 = arc4random_uniform(max - min) + min

    min = UInt32(view.frame.size.height)
    max = UInt32(1000)
    let randomY: UInt32 = arc4random_uniform(max - min) + min

    return CGPointMake(CGFloat(randomX), CGFloat(randomY))
}

Answer 2

只需操纵frame属性：

https://developer.apple.com/library/ios/documentation/UIKit/Reference/UIView_Class/#//apple_ref/occ/instp/UIView/frame

var myButton: UIButton // initialized somehow

// at appropriate time. Idiomatic place is in layoutSubviews() of your custom UIView subclass, but this may be triggered by an action, especially if you're following up immediately with animiation -- up to your design
myButton.frame = CGRect(p, myButton.frame.size)

// now call your animation
UIView.animateWithDuration(/* ... parameters ... */,
    animations: { myButton.frame = /* resting location */ },
    completion: { /* ... */ })

修改

看起来到目前为止的两个答案（美国东部时间8月17日12:46）涵盖了你问题的完全不同的方面，这显然是模棱两可的。他们一起回答了整个问题。

设置视图外的按钮

2 个答案: