Question

我有公司模型和模型Invintaton，公司可以邀请其他公司进行消息传递，现在我只需要展示确认消息传递的公司

class Company < ActiveRecord::Base
  has_many :sent_invitations, class_name: 'Invintation', foreign_key: 'sender_id'
  has_many :invitation_recipients, through: :sent_invitations, source: :recipient 
  has_many :incoming_invitations, class_name: 'Invintation', foreign_key: 'recipient_id'
  has_many :invitation_senders, through: :incoming_invitations, source: :sender
end 

class Invintation < ActiveRecord::Base
  belongs_to :recipient, class_name: 'Company', foreign_key: 'recipient_id'
  belongs_to :sender, class_name: 'Company', foreign_key: 'sender_id'
end

class MessagesController < ApplicationController


  def new
    @company = Company.find(params[:company_id])
    @message = @company.sent_messages.new
    @recipients = Company.joins(:invitation_recipients).where(invitation_recipients: {sender_id: @company.id, confrm: true})
  end
end

但我收到错误SQLite3 :: SQLException：没有这样的列：sent_invitations.confrm：SELECT＆＃34;公司＆＃34;。* FROM＆＃34;公司＆＃34; INNER JOIN＆＃34; invintations＆＃34; ON＆＃34; invintations＆＃34;。＆＃34; sender_id＆＃34; =＆＃34;公司＆＃34;。＆＃34; id＆＃34;在哪里＆＃34; sent_invitations＆＃34;。＆＃34; confrm＆＃34; =＆＃39; t＆＃39;

我知道这种方式只显示发送邀请的公司，这是必要的，并包含邀请

Answer 1

您的查询中至少有两个拼写错误：

sent_invitations.confrm，但应该是sent_invitations.confirm
Invintation，但应该是Invitation

检查您的代码并修复拼写错误，假设未生成具有相同拼写错误的数据库架构。

为什么我收到错误没有这样的列？

1 个答案: