Question

if($band == "something"){
     $que = "BETWEEN '1000' and '2000'";
}

if($band == "somethingelse"){
     $que = "BETWEEN '2000' and '5000'";
}

if($band == "somethingelseelse"){
     $que = "BETWEEN '5000' and '10000'";
}

if($band == "againsomethingelse"){
     $que = "BETWEEN '10000' and '30000'";
}

$query = mysql_query("SELECT * FROM table WHERE col $que order by datetime desc LIMIT 50");

似乎无法找到我在这里失踪的东西......我想在＆＃34;之间找到＆＃34;将语句转换为php变量，以便它将使用给定的输入更改查询项。不同范围有多种不同的输入。当我手动进入之间时（例如SELECT * FROM表WHERE col BETWEEN 1000 AND 2000 order by datetime desc LIMIT 50）我没有问题。它不适用于变量这是我在这里的第一篇文章，所以非常感谢任何帮助！

Answer 1

试试这个：

if($band == "something"){
 $que = "BETWEEN '1000' AND '2000'";
}else{
  $que = "BETWEEN '2000' AND '5000'";
}

 $query = mysql_query("SELECT * FROM table WHERE col $que ORDER BY datetime DESC LIMIT 50");

Answer 2

if($_GET["band"] == "something"){
 $quelow = 1000;
 $quehigh = 2000;

}

if($_GET["band"] == "somethingelse"){
 $quelow = 2000;
 $quehigh = 5000;
}

if($_GET["band"] == "somethingelseelse"){
 $quelow = 5000;
 $quehigh = 10000;
}

if($_GET["band"] == "againsomethingelse"){
 $quelow = 10000;
 $quehigh = 20000;
}

$query = mysql_query("SELECT * FROM table WHERE col BETWEEN $quelow AND $quehigh order by datetime desc LIMIT 50");

我自己解决了这个问题，因为我正在从我的网页上不正确地获取php变量。任何问题都没有问题让我知道！

将php变量BETWEEN statment添加到mysql查询

2 个答案: