Question

所以我对bash很新，我只是编写一个基本脚本来为我运行一个应用程序实用程序。我想要的只是检查输出是否有特定的字符串响应，并记录是否有错误。现在，如果我只使用这一行，我就可以使脚本正常工作

if [[ $condition == *"added"* ]] ; then

一旦我试图寻找一个精确的比较

if [[ "$condition" == "CONDITION:${2} DATE:${3} added" ]] ; then

即使从我能看到的输出是正确的，它也不起作用。我有一种感觉，我正在比较错误或一些秘密字符被添加，这是一个bash功能，我还没有学到。任何帮助将不胜感激。

UPDATE！

因此，根据我给出的反馈，我试图让我的代码更清晰，并了解原始字符串值是什么。感谢大家到目前为止回复。以下是更新的脚本和输出

#!/usr/bin/sh
# This script posts a condition sent to it by the Shout Destination table
# in CCM. Used to generate JOB_LATE incidents.
# If an error is encountered it is logged in the
# job_late_error_log.txt file.
# utility -> ctmcontb -ADD <Condition Name> <Condition Date>
# Condition format -> L@%%JOBNAME-%%NODEID -> JOB_LATE format
# $2 = L@%%JOBNAME-%%NODEID $3 = <Condition Date>
cmd_output=$(ctmcontb -ADD $2 $3)
time_stamp=$(date)
working_directory=/apps/ctm/devsv/scriptsadmin/do_condition/
error_file=job_late_error_log.txt
write_file_to_location=$working_directory$error_file
#if [[ $cmd_output == *"added"* ]] ; then
echo below is the hex output of "CONDITION:${2} DATE:${3} added"
echo "CONDITION:${2} DATE:${3} added" | od -xc
echo below is the command for $cmd_output
echo "$cmd_output" | od -xc
cmd_ouput_no_space = "$(echo -e "${cmd_output}" | tr -d '[[:space:]]')"
echo below is the command with white spaces removed
echo $cmd_ouput_no_space
if [[ "$cmd_ouput_no_space" == "CONDITION:${2} DATE:${3} added" ]] ; then
    echo $cmd_ouput_no_space
    echo successfull ran util
    exit 0
else 
#   echo $cmd_ouput_no_space $time_stamp >> $write_file_to_location
    echo $cmd_ouput_no_space 
    echo error occurred running util
    exit 1
fi

和输出：

ctmtest1-tctmsv80 [9] job_late.sh ctmtest1 u350932-test2 0816
below is the hex output of CONDITION:u350932-test2 DATE:0816 added
0000000     434f    4e44    4954    494f    4e3a    7533    3530    3933
           C   O   N   D   I   T   I   O   N   :   u   3   5   0   9   3
0000020     322d    7465    7374    3220    4441    5445    3a30    3831
           2   -   t   e   s   t   2       D   A   T   E   :   0   8   1
0000040     3620    6164    6465    640a
           6       a   d   d   e   d  \n
0000050
below is the command for CONDITION:u350932-test2 DATE:0816 added
0000000     2043    4f4e    4449    5449    4f4e    3a75    3335    3039
               C   O   N   D   I   T   I   O   N   :   u   3   5   0   9
0000020     3332    2d74    6573    7432    2044    4154    453a    3038
           3   2   -   t   e   s   t   2       D   A   T   E   :   0   8
0000040     3136    2061    6464    6564    0a00
           1   6       a   d   d   e   d  \n
0000051
job_late.sh[19]: cmd_ouput_no_space:  not found
below is the command with white spaces removed


error occurred running util

我不熟悉od -xc调用，但看起来我的值是不同的，这是有道理的。不确定为什么呢？

更新2：

所以我尝试使用line

删除所有空格

cmd_ouput_no_space = "$(echo -e "${cmd_output}" | tr -d '[[:space:]]')"

我在这里找到了：

How to trim whitespace from a Bash variable?

但它似乎不起作用。我已经更新了我原来的脚本并在这篇文章的顶部输出了错误即可。

Answer 1

在捕获的CONDITION中cmd_output之前有一个空格。

bash字符串与嵌套变量的比较

1 个答案: