Question

我正在查看使用GO创建REST API的教程。我正在尝试构建一个Web服务器并提供一个简单的json响应：

package main

import(
    "encoding/json"
    "fmt"
    "net/http"
)

type Payload struct {
    Stuff Data
}

type Data struct {
    Fruit Fruits
    Veggies Vegetables
}

type Fruits map[string]int
type Vegetables map[string]int

func serveRest(w http.ResponseWriter, r *http.Request) {
    response, err := getJsonResponse()
    if err != nil {
        panic(err)
    }

    fmt.Fprintf(w, string(response))
}

func main() {
    http.HandleFunc("/", serveRest)
    http.ListenAndServe("localhost:7200", nil)
}

func getJsonResponse() ([]byte, error){
    fruits := make(map[string]int)
    fruits["Apples"] = 25
    fruits["Oranges"] = 11

    vegetables := make(map[string]int)
    vegetables["Carrots"] = 21
    vegetables["Peppers"] = 0

    d := Data(fruits, vegetables)
    p := Payload(d)

    return json.MarshalIndent(p, "", "  ") 
}

当我运行此代码时，我收到错误：

too many arguments to conversion to Data: Data(fruits, vegetables)

我不明白为什么它抛出那个错误，因为它期待2个参数而且我传递了2个参数。这是我尝试GO的第一天，所以也许我错过了一些概念或什么。

创建一个简单的Json响应GO

0 个答案: