我有两个表 - 一个是存储文章内容，另一个是存储文章注释
我用来显示这些的功能是：
function list_articles() {
include('core/db/db_connection.php');
$sql = "SELECT blog.content_id, blog.title, blog.content, blog.posted_by, blog.date, article_comments.comments, article_comments.comment_by
FROM blog LEFT OUTER JOIN article_comments
ON blog.content_id = article_comments.blog_id
WHERE blog.content != ''
ORDER BY blog.content_id DESC";
$result = mysqli_query($dbCon, $sql);
$previous_blog_id = 0;
while ($row = mysqli_fetch_array($result)) {
if ($previous_blog_id != $row['content_id']) {
echo "<h5 class='posted_by'>Posted by {$row['posted_by']} on {$row['date']}</h5>
<h1 class='content_headers'>{$row['title']}</h1>
<article>{$row['content']}</article>
<hr class='artline'>";
$previous_blog_id = $row['content_id'];
}
if (!empty($row['comment_by']) && !empty($row['comments'])) {
echo "<div class='commented_by'>Posted by: {$row['comment_by']} </div>
<div class='comments'>Comments: {$row['comments']}</div>
<hr class='artline2'>";
}
}
}
我使用以下内容在article_comments表中插入注释：
function insert_comments($comments, $comment_by, $blog_id) {
include('core/db/db_connection.php');
$comment_by = sanitize($comment_by);
$comments = sanitize($comments);
$sql = "INSERT INTO article_comments (comments, comment_by, blog_id)
VALUES ('$comments', '$comment_by', '$blog_id')";
mysqli_query($dbCon, $sql);
}
这有效 - 它会插入，但我不知道如何在用户提交帖子时如何定位$ blog_id变量...以下是我使用的表单
<?php echo list_articles();
if (!empty($_POST)) {
insert_comments($_POST['comments'], $_POST['username'], 11);
}
?>
<form method='post' action='' class='comments_form'>
<input type='text' name='username' placeholder='your name... *' id='name'>
<textarea name='comments' id='textarea' placeholder='your comment... *' cols='30' rows='6'></textarea>
<input type='submit' name='submit' id='post' value='post'>
</form>
我敢打赌你注意到我已经手动插入11作为最后一个变量的参数。这链接到我的article_comments表中的blog_id 11（外键）。它正好显示评论。
有没有办法定位$ blog_id而无需手动插入数字？我是如何使用$_POST['comments']定位$ comments变量的？
此外，即使我可以定位，我如何知道用户评论的帖子？我应该在下拉列表中为他们提供选择吗？这看起来很尴尬..但它是我能想到的唯一解决方案。
编辑：我尝试在隐藏字段中定位blog_id：
function list_articles() {
include('core/db/db_connection.php');
$sql = "SELECT blog.content_id, blog.title, blog.content, blog.posted_by, blog.date, article_comments.comments, article_comments.comment_by
FROM blog LEFT OUTER JOIN article_comments
ON blog.content_id = article_comments.blog_id
WHERE blog.content != ''
ORDER BY blog.content_id DESC";
$result = mysqli_query($dbCon, $sql);
$previous_blog_id = 0;
while ($row = mysqli_fetch_array($result)) {
if ($previous_blog_id != $row['content_id']) {
echo "<h5 class='posted_by'>Posted by {$row['posted_by']} on {$row['date']}</h5>
<h1 class='content_headers'>{$row['title']}</h1>
<article>{$row['content']}</article>
<hr class='artline'>";
$previous_blog_id = $row['content_id'];
}
if (!empty($row['comment_by']) && !empty($row['comments'])) {
echo "<div class='commented_by'>Posted by: {$row['comment_by']} </div>
<div class='comments'>Comment: {$row['comments']}</div>
<hr class='artline2'>";
}
$sql2 = "SELECT FROM article_comments VALUES blog_id";
$result2 = mysqli_query($dbCon, $sql2);
while ($row = mysqli_fetch_assoc($result2)) {
echo " <form method='post' action='' class='comments_form'>
<input type='text' name='username' placeholder='your name... *' id='name'>
<textarea name='comments' id='textarea' placeholder='your comment... *' cols='30' rows='6'></textarea>
<input type='hidden' name=blog_id' value='{$row['blog_id']}'>
<input type='submit' name='submit' id='post' value='post'>
</form>";
}
}
}
sql2和result2部分是导致错误的语句
编辑2：
我不认为$ sql2是正确的方法。代码现在工作正常，但我回到了正方形1.对于每个注释，插入的文章都会重复。
<form method='post' action='' class='comments_form'>
<input type='text' name='username' placeholder='your name... *' id='name'>
<textarea name='comments' id='textarea' placeholder='your comment... *' cols='30' rows='6'></textarea>
<input type='hidden' name=blog_id' value='{$row['blog_id']}'>
<input type='submit' name='submit' id='post' value='post'>
</form>";
有没有办法在没有调用while（$ row = mysqli_fetch_array（$ result））{}的情况下定位blog_id？或者至少在第二次循环中没有调用它？
使用我发布的第一段代码，我得到以下结果：
Article title: LOREM IPSUM
Content: LOREM IPSUM DOLOR SIT AMET....
--------------------------------------
Name: DSK
Comment: Great article!
--------------------------------------
Name: DSK
Comment: Great article! - 2nd comment
-- BEGIN SECOND ARTICLE ON WEBPAGE
Article title: LOREM IPSUM 2nd article
Content: LOREM IPSUM DOLOR SIT AMET....
--------------------------------------
Name: User0
Comment: Great article!
--------------------------------------
Name: User1
Comment: Great article! - 2nd comment
--------------------------------------
Name: User2
Comment: Great article! - 3rd comment
--------------------------------------
这正是我正在寻找的。但是我只能通过phpmyadmin接口插入注释，手动选择外键（blog_id）。
我希望能够通过表单获得相同的结果：
Article title: LOREM IPSUM
Content: LOREM IPSUM DOLOR SIT AMET....
-------------------------------------- //comments
Name: DSK
Comment: Great article!
--------------------------------------
Name: DSK
Comment: Great article! - 2nd comment
-------------------------------------- // end comments
|-------------------------------------| // comments form
|Name: New User |
|Comment: New comment ! |
| |
|-------------------------------------|
[Submit]
当用户提交表单时，他的姓名和评论会被提交到数据库中的article_comments表中。外键（blog_id）也应链接到现有文章（它所做的）。我只需要一种方法来在我的函数中定位它。
这有意义吗？....
答案 0 :(得分：1)
也许您可以在表单中使用隐藏的表单元素：
<input type="hidden" name="blog_id" value="<?PHP echo $id;?>">
然后在提交时你可以用$ _POST访问它[＆＃34; blog_id＆＃34;]
如果我理解你的问题是正确的。