Question

我尝试了以下代码，但它不起作用。

代码

<?php
if (!empty($_POST)) {
     $mysqli = new mysqli('localhost', 'root', '123', 'users');

     if ($mysqli->connect_error) {
        die( 'Connect Error: ' . $mysqli->connect_errno . ': ' . $mysqli->connect_error );
     }

     $sql = "INSERT INTO users ( username, email ) VALUES ( '{$mysqli->real_escape_string($_POST['username'])}', '{$mysqli->real_escape_string($_POST['email'])}' )";
     $insert = $mysqli->query($sql);

     if ($insert) {
        echo "Success! Row ID: {$mysqli->insert_id}";
     } else {
        die("Error: {$mysqli->errno} : {$mysqli->error}");
     }

     $mysqli->close();
}
?>
<form action="main.php" method="post">
    <input type="text" id="SIMOMO"  name="username" minlegth="5" maxlength="30" class="pad" required> 
    <input type="text" ID="FLOBIT"name="email" class="pad" required >
    <input type="submit">
</form>

Answer 1

试试这个：

<?php  
if ($_POST['sub']) {
$server = "localhost";
$username = "yourusernamehere";
$pass = "yourpasswordhere";
$db = "users";
// Create connection
$mysqli = new mysqli($server, $username, $pass, $db);
// Check connection
if ($mysqli->connect_error) {
    die("Connection failed: " . $mysqli->connect_error);
}
echo "Connected successfully";


$uname = mysql_escape_string($_POST['username'])
$mail = mysql_escape_string($_POST['email']);        
$sql = "INSERT INTO users (username, email) VALUES ('$uname', '$mail')";
$insert = $mysqli->query($sql);
if ($insert){
  echo "Success! Row ID: {$mysqli->insert_id}";
  header("Location:main.php");
  } else {
   die("Error: {$mysqli->errno} : {$mysqli->error}");
  }
  $mysqli->close();
        }
?>


<!DOCTYPE html>
<html>
<body>
        <form action = "" method = "POST">
        <label>Enter your Username:</label>
        <input type="text"  name="username" required>
        <label>Enter your Email:</label>        
        <input type="email"  name="email" required >
         <input type="hidden" name = "check">
         <input type="submit" name = "sub" value = "INSERT">
        </form>
</body>
</html>

在第三行查看的数据库名称为'users'等等是您尝试INSERT INTO进入的表格的名称 "users'第10行。你确定你没有弄乱吗？

无法使用php和sql

1 个答案: