将指针指针与字符进行比较？

Question

我有一个字符数组。指针指向该字符数组。另外，另一个指针指向该指针，即它是指向指针的指针。现在，我需要将指针指针与字符文字进行比较，比如＆＃34; a＆＃34;。

我尝试过strcmp，但它没有用。

我该怎么做？

    char arr[1000];
    char *ptr,*ptr1,**curr;
    ptr=arr;        //pointer pointer to that array
    curr=&ptr;      //pointer to a pointer
    if(**curr=='.') //doesn't work
        printf("Some code");

Answer 1

如果我理解正确您正在谈论以下

#include <string.h>

//...

char arr[1000] = "a";
char *ptr = arr;
char **curr = &ptr;

if ( strcmp( *curr, "a" ) == 0 ) puts( "They are equal" );

或者

#include <string.h>

//...

char arr[1000] = "abcd";
char *ptr = arr;
char **curr = &ptr;
char *ptr2 = "ab";

if ( strncmp( *curr, ptr2, strlen( ptr2 ) ) == 0 ) puts( "They are equal" );

如果您需要比较单个字符，则可以编写

char arr[1000] = "a";
char *ptr = arr;
char **curr = &ptr;

if ( **curr == 'a' ) puts( "They are equal" );

或

char arr[1000] = "ab";
char *ptr = arr;
char **curr = &ptr;

if ( ( *curr )[1] == 'b' ) puts( "They are equal" );