从gulp-watch抛出类型错误中排除子目录

Question

我正在运行以下监视任务：

gulp.task('watch', function() {

    gulp.watch('./ui/scss/*.scss', ['styles']);
    gulp.watch('./js/*.js', '!./js/vendor/*.js', ['scripts']);
    gulp.watch('./**/*.html', ['html']);

});

但它似乎抛出以下错误？...

TypeError: Cannot assign to read only property 'mark' of !./js/vendor/*.js at new Gaze

Answer 1

手表的第二个参数必须声明为数组

gulp.watch('src...', ['taskname', ......];