Question

我的想法是创造出从天而降的块。

要做到这一点，我需要一个自定义动作，它可以做四件事：

使用我的块类
设置该节点的位置
将节点添加到场景
延迟后转到第一点

我想知道你是否真的可以创建SKAction.customActionWithDuration来做这件事。

提前致谢

Answer 1

The following method creates an SKAction that should fit your needs.

func buildAction() -> SKAction {
    return SKAction.runBlock {
        // 1. Create a node: replace this line to use your Block class
        let node = SKShapeNode(circleOfRadius: 100)

        // 2. Set the position of that node
        node.position = CGPoint(x: 500, y: 300)

        // 3. add the node to the scene
        self.addChild(node)

        // 4. after a delay go to point one
        let wait = SKAction.waitForDuration(3)
        let move = SKAction.moveTo(CGPoint(x: 500, y: 0), duration: 1)
        let sequence = SKAction.sequence([wait, move])
        node.runAction(sequence)
    }
}

Answer 2

感谢@appsYourLife。我在下面做了几处修改：

我已经调整了swift 3

我添加了一个名为parent的参数，因此您可以使用buildAction(parent: self)，或者如果您想将节点附加到其他某个节点，则可以使用buildAction(parent: otherNode)

func buildAction(parent: SKNode) -> SKAction {
  return SKAction.run {

  // 1. Create a node: replace this line to use your Block class
  let node = SKShapeNode(circleOfRadius: 100)
  // 2. Set the position of that node
  node.position = CGPoint(x: 500, y: 300)

  // 3. add the node to the scene
  parent.addChild(node)

  // 4. after a delay go to point one
  let wait = SKAction.wait(forDuration: 3)
  let move = SKAction.move(to: CGPoint(x: 500, y: 0), duration: 1)
  let sequence = SKAction.sequence([wait, move])
  node.run(sequence)
 }
}

如何在swift中创建自定义SKAction

2 个答案: