我第一次使用auth0生成令牌来保护与我的网络服务的连接。
我用它来记录 - 我通过电子邮件＆amp;密码这是我的网址，我得到了令牌
这是我的代码，工作正常
public String post_to_webservice() {
final StringBuilder stringBuilder = new StringBuilder();
final String[] line = {null};
final BufferedReader[] reader = {null};
new Thread(new Runnable() {
@Override
public void run() {
try {
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("email", "test"));
params.add(new BasicNameValuePair("password", "test"));
URL url = new URL("https://validate.co.nz/api/public/api/authenticate");
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setRequestMethod("POST");
connection.setReadTimeout(30000);
OutputStream outputStream = connection.getOutputStream();
BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(outputStream, "UTF-8"));
writer.write(getQuery(params));
writer.flush();
writer.close();
outputStream.close();
connection.connect();
if (connection.getResponseCode() == HttpURLConnection.HTTP_OK) {
reader[0] = new BufferedReader(new InputStreamReader(connection.getInputStream()));
while ((line[0] = reader[0].readLine()) != null) {
stringBuilder.append(line[0]);
}
}
} catch (Exception e) {
e.printStackTrace();
} finally {
if (reader[0] != null) {
try {
reader[0].close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
runOnUiThread(new Runnable() {
@Override
public void run() {
try {
String message = stringBuilder.toString();
JSONObject object = new JSONObject(message);
Token = (String) object.get("token");
Toast.makeText(MainActivity.this, "token is : " + Token, Toast.LENGTH_LONG).show();
} catch (Exception e) {
e.printStackTrace();
}
}
});
}
}).start();
return stringBuilder.toString();
}
private String getQuery(List<NameValuePair> params) throws UnsupportedEncodingException {
StringBuilder result = new StringBuilder();
boolean first = true;
for (NameValuePair pair : params) {
if (first)
first = false;
else
result.append("&");
result.append(URLEncoder.encode(pair.getName(), "UTF-8"));
result.append("=");
result.append(URLEncoder.encode(pair.getValue(), "UTF-8"));
}
return result.toString();
}
但是我需要使用相同的url，但是通过传递我的令牌获取请求来获取数据 在标题
这是我的尝试
public String get_request() {
final StringBuilder stringBuilder = new StringBuilder();
final String[] line = {null};
final BufferedReader[] reader = {null};
final String[] result = {null};
new Thread(new Runnable() {
@Override
public void run() {
try {
// second try pass token here
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("token", Token));
URL url = new URL("https://validate.co.nz/api/public/api/authenticate");
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
// I try put my token in header but its fail
String base64Auth = Base64.encodeToString(Token.getBytes(), Base64.NO_WRAP);
connection.setRequestProperty("Authorization", "Basic " + base64Auth);
connection.setRequestProperty("Content-Type", "application/json;charset=utf-8");
connection.setRequestProperty("Accept-Charset", "UTF-8");
connection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded;charset=UTF-8");
connection.setRequestMethod("GET"); // get request
connection.setReadTimeout(300000);
connection.setDoOutput(true);
connection.setDoInput(true);
OutputStream outputStream = connection.getOutputStream();
BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(outputStream, "UTF-8"));
writer.write(getQuery(params));
writer.flush();
writer.close();
outputStream.close();
connection.connect();
if (connection.getResponseCode() == HttpURLConnection.HTTP_OK) {
reader[0] = new BufferedReader(new InputStreamReader(connection.getInputStream()));
while ((line[0] = reader[0].readLine()) != null) {
stringBuilder.append(line[0]);
}
result[0] =stringBuilder.toString();
}
} catch (Exception e) {
e.printStackTrace();
result[0] = e.getMessage();
} finally {
if (reader[0] != null) {
try {
reader[0].close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
runOnUiThread(new Runnable() {
@Override
public void run() {
Toast.makeText(MainActivity.this, "Result: " + result[0], Toast.LENGTH_LONG).show();
}
});
}
}).start();
return result[0];
}
我收到此错误未发现身份验证质询 任何建议谢谢
答案 0 :(得分：1)
我正在开发一款Android应用，该应用使用OAuth身份验证来验证对RESTful Web服务的请求。我对您使用的特定OAuth包一无所知，也无法确定您遇到的问题的原因。但是，根据你在做什么和我在做什么之间的差异，我看到两个潜在的问题：
您可能没有在HTTP标头中使用正确的标记。特别是，您使用的令牌可能是刷新令牌而不是访问令牌，您可能需要使用访问令牌。
您可能错误地在标头中插入了令牌。就我而言，我使用以下方法插入令牌：
connection.setRequestProperty("Authorization", "Bearer " + accessToken);
答案 1 :(得分：1)
我认为问题可能是setDoOutput()，我测试了这个示例代码，你可以阅读我的评论
private class APIRequest extends AsyncTask<Void, Void, String> {
@Override
protected String doInBackground(Void... params) {
try {
String token = "0123456789";
URL url = new URL("https://validate.co.nz/api/public/api/authenticate");
HttpsURLConnection urlConnection = (HttpsURLConnection) url.openConnection();
urlConnection.setDoInput(true);
urlConnection.setDoOutput(true); //HERE: if TRUE, receive "No authentication challenges found"; if FALSE, receive "token_not_provided"
urlConnection.setRequestMethod("GET"); // I think if GET, should setDoOutput(false);
urlConnection.setRequestProperty("Authorization", "Basic " + token);
urlConnection.connect();
InputStream inputStream;
if (urlConnection.getResponseCode() != HttpURLConnection.HTTP_OK) {
inputStream = urlConnection.getErrorStream();
} else {
inputStream = urlConnection.getInputStream();
}
return String.valueOf(urlConnection.getResponseCode()) + " " + urlConnection.getResponseMessage();
} catch (Exception e) {
return e.toString();
}
}
@Override
protected void onPostExecute(String response) {
super.onPostExecute(response);
}
}