Question

我在这里得到了一个很好的解决方案，但正则表达式将字符串拆分为“”字符串以及我需要的其他2个分割。

String  Result = "<ahref=https://blabla.com/Securities_regulation_in_the_United_States>Securities regulation in the United States</a> - Securities regulation in the United States is the field of U.S. law that covers transactions and other dealings with securities.";

String [] Arr =  Result.split("<[^>]*>");
for (String elem : Arr) {
    System.out.printf(elem);
}

结果是：

Arr[0]= ""
Arr[1]= Securities regulation in the United States
Arr[2]= Securities regulation in the United States is the field of U.S. law that covers transactions and other dealings with securities.

Arr[1]和Arr[2]拆分很好我只能摆脱Arr[0]。

Answer 1

你可以使用相反的正则表达式来捕获你想要的东西，使用这样的正则表达式：

(?s)(?:^|>)(.*?)(?:<|$)

<强> Working demo

<强> IDEOne Code working

代码：

String line = "ahref=https://blabla.com/Securities_regulation_in_the_United_States>Securities regulation in the United States</a> - Securities regulation in the United States is the field of U.S. law that covers transactions and other dealings with securities.";

Pattern pattern = Pattern.compile("(?s)(?:^|>)(.*?)(?:<|$)");
Matcher matcher = pattern.matcher(line);
while (matcher.find()) {
    System.out.println("group 1: " + matcher.group(1));
}

Answer 2

如果仅使用split，则无法避免该空字符串，尤其是因为正则表达式不是零长度。

您可以尝试删除在输入开头放置的第一个匹配项，然后拆分其余匹配项，例如

String[] Arr =  Result.replaceFirst("^<[^>]+>","").split("<[^>]+>")

但通常你应该avoid using regex with HTML\XML 。 Try using parser instead，如Jsoup。

用正则表达式提取数据

2 个答案: