我是java的新手,我想提供的密钥是" aaa"并获得价值" bbb"从下面的xml文件。
<?xml version="1.0" encoding="UTF-8"?>
<configuration>
<General>
<add key="aaa" value="bbb"/>
</General>
</configuration>
这是我的代码无效:
Properties prop = new Properties();
InputStream is = new FileInputStream("c:\\propFileName.config");
prop.load(is);
String result = prop.getProperty("aaa");
请帮忙!
答案 0 :(得分:2)
将此用于此类xml文件:
try {
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
Document doc = builder.parse("E:\\temp\\dist\\filename.config");
XPathFactory xPathfactory = XPathFactory.newInstance();
XPath xpath = xPathfactory.newXPath();
XPathExpression expr = xpath.compile("//configuration/General/add[@key]");
NodeList nl = (NodeList) expr.evaluate(doc, XPathConstants.NODESET);
for (int c = 0; c < nl.getLength(); c++) {
Node currentItem = nl.item(c);
String key = currentItem.getAttributes().getNamedItem("key").getNodeValue();
String value = currentItem.getAttributes().getNamedItem("value").getNodeValue();
urlList.put(key, value);
}
} catch (Exception e) {
e.printStackTrace();
}