Question

我的XML如下所示：

<status_log>
  <log>
    <status>CREATED</status>
    <detail></detail>
    <datetime>03/17/2015 10:06:02</datetime>
  </log>
  <log>
    <status>AC_VALIDATION</status>
    <detail>Credit Transaction Response: 0 - , Error:  -</detail>
    <datetime>03/17/2015 10:06:04</datetime>
  </log>
  <log>
    <status>CREATED</status>
    <detail>Debit Transaction Response: 0 - , Error:  -</detail>
    <datetime>03/17/2015 10:06:05</datetime>
  </log>
  <log>
    <status>INVALID</status>
    <detail>Request ID: 110895, Transaction Number: A92C18E9 ,Status: 9, Error Code: 0</detail>
    <datetime>03/18/2015 20:14:34</datetime>
  </log>
  <log>
    <status>UPDATED</status>
    <detail></detail>
    <datetime>03/19/2015 06:06:03</datetime>
  </log>
  <log>
    <status>AC_VALIDATION</status>
    <detail>Credit Transaction Response: 0 - , Error:  -</detail>
    <datetime>03/19/2015 06:06:05</datetime>
  </log>
  <log>
    <status>CREATED</status>
    <detail>Debit Transaction Response: 0 - , Error:  -</detail>
    <datetime>03/19/2015 06:06:05</datetime>
  </log>
  <log>
    <status>UPDATED</status>
    <detail></detail>
    <datetime>03/19/2015 06:06:12</datetime>
  </log>
</status_log>

我想仅为在<log>子元素中具有信用交易响应的元素获取<detail> xml。

Answer 1

您只需要Where扩展方法来过滤： -

var result = xdoc.Descendants("log")
                .Where(x => (string)x.Element("detail") == "Credit Transaction Response");

<强>更新

如果您只想按Credit Transaction Response过滤，而不是按完整文字进行过滤，则可以使用StartsWith，如下所示： -

var result = xdoc.Descendants("log")
                 .Where(x => (string)x.Element("detail") != null  
       ? x.Element("detail").Value.ToString().StartsWith("Credit Transaction Response") 
       : false);

如何通过使用LINQ搜索特定的字符串/文本来获取xml日志元素

1 个答案: