Question

我目前有以下表格：

TABLE klusbonnen_deelnemers:
bonnummer (varchar) - order number
adres (varchar) - order adres
deelnemer (varchar) - user
binnen (date) - date order received
klaar (date) - original order milestone
datum_gereed (date) - date order completed
gereed (varchar) - YES or NO (YES= completed NO= Not yet completed)
datum_factuur (date) - date when user marked order completed (button clicked)
factuur (varchar) - weeknumber order completed

一个订单（bonnummer）可以有多个用户（deelnemer），他们都必须标记订单“已完成”（datum_gereed）。只有当所有用户（deelnemer）标记订单（bonnummer）“已完成”（datum_gereed）时，订单才“完成”。我正在尝试编写一个查询，它给了我：所有已完成的订单（bonnummer）在给定的时间跨度内（上个月）。然而... 完成日期（datum_gereed）应保留最后日期（因为这是实际的完成日期）。该列表应该具有最新的“标记完成”日期（datum_factuur）的订单（bonnummer）（排序DESC）（当然只有当所有用户（deelnemer）完成订单时（所有用户（deelnemers）具有gereed =“ YES“）

到目前为止我有这个：

SELECT  DISTINCT tbl1.bonnummer AS 'KLUSBONNUMMER', tbl1.adres AS 'ADRES',
        tbl1.binnen AS 'BINNENGEKOMEN OP', tbl1.klaar AS 'ORIGINELE STREEFDATUM',
        tbl1.datum_gereed AS 'GEREEDGEKOMEN OP', tbl1.factuur AS 'WEEKNUMMER'
    FROM  klusbonnen_deelnemers AS tbl1
    INNER JOIN  
      ( SELECT  tbl2.bonnummer
            FROM  klusbonnen_deelnemers AS tbl2
            WHERE  tbl2.bonnummer NOT IN (
                SELECT  tbl3.bonnummer
                    FROM  klusbonnen_deelnemers AS tbl3
                    WHERE  tbl3.gereed = 'NEE')
      ) AS tbl4 ON tbl1.bonnummer = tbl4.bonnummer
    INNER JOIN  
      ( SELECT  bonnummer, MAX(datum_gereed) AS 'MAXDATUM'
            FROM  klusbonnen_deelnemers
            GROUP BY  bonnummer
      ) MAXFILTER ON tbl1.bonnummer = MAXFILTER.bonnummer
      AND  tbl1.datum_gereed = MAXFILTER.MAXDATUM
    WHERE  tbl1.datum_factuur BETWEEN NOW() - INTERVAL 2 MONTH AND NOW()
    ORDER BY  tbl1.bonnummer DESC

此查询有效，但我认为这可以通过更简单的方式完成。最重要的是，查询仅适用于我的navicat编辑器。在我的“实时”网站上调用此查询会产生错误（WHERE子句中的子查询...）（我确实所有登录都正确，因为其他查询可以正常工作）。

有谁可以帮助（简化）此查询？ THX ...

Answer 1

这一部分：

INNER JOIN (SELECT tbl2.bonnummer
FROM klusbonnen_deelnemers AS tbl2
WHERE tbl2.bonnummer NOT IN 
(SELECT tbl3.bonnummer 
FROM klusbonnen_deelnemers AS tbl3
WHERE tbl3.gereed = 'NEE')) AS tbl4
ON tbl1.bonnummer = tbl4.bonnummer

似乎没用。尝试在“最底层” - gereed <> 'NEE'

中使用WHERE

SELECT DISTINCT
        kd.bonnummer    AS 'KLUSBONNUMMER',
        kd.adres        AS 'ADRES',
        kd.binnen       AS 'BINNENGEKOMEN OP',
        kd.klaar        AS 'ORIGINELE STREEFDATUM',
        kd.datum_gereed AS 'GEREEDGEKOMEN OP',
        kd.factuur      AS 'WEEKNUMMER'
    FROM klusbonnen_deelnemers AS kd
    INNER JOIN (
            SELECT bonnummer, MAX(datum_gereed) AS 'MAXDATUM'
            FROM klusbonnen_deelnemers 
            GROUP BY bonnummer
        ) AS MAXFILTER 
        ON (kd.bonnummer = MAXFILTER.bonnummer AND kd.datum_gereed = MAXFILTER.MAXDATUM)
    WHERE
        kd.gereed <> 'NEE' 
        kd.datum_factuur BETWEEN NOW() - INTERVAL 2 MONTH AND NOW()
    ORDER BY 
        kd.bonnummer DESC

简化我的mysql查询

1 个答案: