有人可以告诉我如何从字符串中获取子字符串吗?我用substring和rangeOfString方法尝试了所有方法,但无法解决它... 我的文字是这样的:
var text = "Suuuuper, {1} has sent {2} a very cool present"
我的文字可以在{1}之前和{2}之后变化,所以我想我必须首先得到" {1}"的索引。和" {2}"然后得到子串。
我想最终:
var myTextBefore{1}: String = ...
var myTextAfter{2}: String = ...
提前致谢。
答案 0 :(得分:3)
您可以使用#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'INNER JOIN price
ON stock.stock_code = price.stock_code
WHERE stock.stoc' at line 3
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var imgSrc = url.createObjectURL(blob);
var img = new Image();
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img.onload = function () {
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pdf.addImage(img, 0, 0, img.width, img.height);
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和rangeOfString
方法:
substringToIndex