Question

我有下一个代码：

$rez1 = mysqli_query($kon, "SELECT producten.id as prodID, producten.*, product_shop_tt.*, product_shop_tt.id AS prshID FROM producten 
                            INNER JOIN product_shop_tt ON producten.id = product_shop_tt.product_id 
                            WHERE product_shop_tt.shop_id = ". $red["id"] ."");
$brRez = mysqli_num_rows($rez1);
$i = 1;

while($red1 = mysqli_fetch_assoc($rez1)){
    $rezOrdDet = mysqli_query($kon, "SELECT COUNT(producten.id) as count FROM order_details 
                                     INNER JOIN product_shop_tt ON order_details.product_shop_tt_id = product_shop_tt.id
                                     INNER JOIN producten ON producten.id = product_shop_tt.product_id
                                     WHERE product_shop_tt_id = ". $red1["prshID"] ." ORDER BY count DESC");
    $br = mysqli_num_rows($rezOrdDet);
    while($rez = mysqli_fetch_assoc($rezOrdDet)){
        echo "Result : " . $rez["count"] . "<br />";
    }
}

我的问题是我得到的结果。我希望得到按计数排序的结果，但我无法做到正确。我希望order_details表中最常出现的结果显示在其余部分之上。我得到下一个结果（数字是计数值）：

Result : 3
Result : 4
Result : 2
Result : 3

这不是正确的顺序。我想要像

这样的东西

Result : 4
Result : 3
Result : 3
Result : 2

问题是我现在得到随机结果，我想要的是结果按count的值排序。第一张照片是我得到的，第二张照片是我想要的。

Answer 1

尝试将count放入`（倾斜）符号

$newArr = array();
$rez1 = mysqli_query($kon, "SELECT producten.id as prodID, producten.*, 
                            product_shop_tt.*, product_shop_tt.id AS prshID FROM producten 
                             INNER JOIN product_shop_tt ON producten.id = product_shop_tt.product_id 
                            WHERE product_shop_tt.shop_id = ". $red["id"] ."");
$brRez = mysqli_num_rows($rez1);
$i = 1;
while($red1 = mysqli_fetch_assoc($rez1))
{
    $rezOrdDet = mysqli_query($kon, "SELECT COUNT(producten.id) as `count` FROM order_details 
                                                     INNER JOIN product_shop_tt ON order_details.product_shop_tt_id = product_shop_tt.id
                                                     INNER JOIN producten ON producten.id = product_shop_tt.product_id
                                                     WHERE product_shop_tt_id = ". $red1["prshID"] ." ORDER BY `count` DESC");
    $br = mysqli_num_rows($rezOrdDet);
    while($rez = mysqli_fetch_assoc($rezOrdDet))
    {
        $newArr[] = $rez["count"];
    }
}

rsort($newArr);

Answer 2

好吧，我认为那里的杆子错了。

您是否尝试按订单数量订购产品？

尝试单个查询。如果没有看到您的架构，那么按照当前的查询会有点困难，但您可以尝试以下方法：

"SELECT producten.*, product_shop_tt.*, COUNT(order_details.id) AS order_count from producten
  INNER JOIN product_shop_tt ON producten.id = product_shop_tt.product_id
  LEFT JOIN order_details ON order_details.product_shop_tt_id = product_shop_tt.id
  WHERE product_shop_tt.shop_id = '" . $red['id'] . "'
  GROUP BY producten.id
  ORDER BY order_count DESC"

Answer 3

您应该使用单个查询 -

"SELECT p.id as prodID, p.*, s.*, 
s.id AS prshID, COUNT(p.id) as res_count 
FROM producten p 
INNER JOIN product_shop_tt s ON p.id = s.product_id 
INNER JOIN order_details o on o.product_shop_tt_id = s.id
WHERE s.shop_id = ". $red["id"] ."
ORDER BY res_count DESC"

Answer 4

您还可以按顺序使用列序列号

和你一样，你可以使用order by 1 desc

此处按1表示结果的第一列，依此类推。

如何按计数订购

4 个答案: