从CSV字段中选择IN

Question

我在MySQL数据库中有以下内容

CHILDREN 
|NAME |LIKES (LONGTEXT)
|Sam  |75
|John |58,64,75

FRUITS 
|ID |LABEL
|58 |Apple
|64 |Banana
|75 |Cherry

为了获得儿童的水果名称，我做了：

> select * from fruits where id in 
(select LIKES from CHILDREN where name="Sam");
|ID |LABEL
|75 |Cherry    

好的，但是

> select * from fruits where id in 
(select LIKES from CHILDREN where name="John");
|ID |LABEL
|58 |Apple

我也尝试了以下相同的结果：

> select * from fruits where id in ("58,64,75")
|ID |LABEL
|58 |Apple
[Main Instruction]
Your query produced 1 warnings.
Warning: Truncated incorrect DOUBLE value: '58,64,75'
[OK]

>select * from fruits where id in (58,64,75)
|ID |LABEL
|58 |Apple
|64 |Banana
|75 |Cherry

如何解决问题无需更改表格定义以及类似的内容......