Question

我有实体开发人员和评论和关系很多评论给一个开发人员。当我看到开发人员的所有评论和编辑时，我需要表格 - 在数据库中添加，删除。这个问题有哪些解决方案

实体评论：

class Comments
{
    /**
     * @var integer
     *
     * @ORM\Column(name="id", type="integer")
     * @ORM\Id
     * @ORM\GeneratedValue(strategy="AUTO")
     */
    private $id;

    /**
     * @ORM\ManyToOne(targetEntity="Developer", inversedBy="comments")
     * @ORM\JoinColumn(name="talent_id", nullable = true, referencedColumnName="id")
     * */
    protected $talent;

    /**
     * @var string
     *
     * @ORM\Column(name="added_by", type="string", length=10, nullable=true)
     */
    private $added_by;

    /**
     * @var string
     *
     * @ORM\Column(name="comment", type="string", length=10, nullable=true)
     */
    private $comment;

实体开发者：

class Developer extends CustomUser
{
    /**
     * @var integer
     *
     * @ORM\Column(name="id", type="integer")
     * @ORM\Id
     * @ORM\GeneratedValue(strategy="AUTO")
     */
    private $id;
    /////
    /**
     * @ORM\OneToMany(targetEntity="Comments", mappedBy="talent",  cascade={"persist", "remove"})
     */
    protected $comments;

也许需要表格形式，但如何做到这一点？

Answer 1

您正在寻找字段类型collection。

示例usage of collection type

Answer 2

class Comments
{
....
/**
*
*@ORM\ManyToOne(targetEntity="Developer", inversedBy="developer_to_comments")
* @ORM\JoinColumn(name="developer_to_comments_id", referencedColumnName="id", nullable=false)
*
*/
private $comments_to_developer;
...
}

和班级开发人员

class Developer extends CustomUser
{
....
/**
*
* @var ArrayCollection
* @ORM\OneToMany(targetEntity="Comments", mappedBy="comments_to_developer", cascade={"remove"})
*/
private $developer_to_comments;

public function __construct()
{
  $this->developer_to_comments = new ArrayCollection();
}
....
}

不要忘记use Doctrine\Common\Collections\ArrayCollection

Symfony ManyToOne表单在DB中添加，删除

2 个答案: