我正在尝试使用以下代码向终端发送ISO8583请求:
try {
XMLParser packager = new XMLParser(this.xmlFile);
final ISOMsg isoMsg = new ISOMsg();
isoMsg.setPackager(packager);
isoMsg.setMTI("0800");
isoMsg.set(3, "xxxxxx");
isoMsg.set(7, "xxxxxxxxxx"); //MMDDhhmmss
isoMsg.set(11, "xxxxxx");
isoMsg.set(12, "084500"); //Time of the message HHmmss
isoMsg.set(13, "0621"); //Date MMDD
isoMsg.set(41, "xxxxxxxx");
isoMsg.set(62,"xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx");
isoMsg.set(63,"xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx");
BaseChannel channel = new BaseChannel() {};
channel.setLogger(logger, "server-request-channel");
channel.setHeader(isoMsg.pack());
channel.setHost("xx.xx.xx.xx", xxxxx);
ISOMUX isoMux = new ISOMUX(channel) {
@Override
protected String getKey(ISOMsg m) throws ISOException {
return super.getKey(m);
}
};
isoMux.setLogger(logger, "server-request-mux");
new Thread(isoMux).start();
ISORequest req = new ISORequest(isoMsg);
isoMux.queue(req);
req.setLogger(logger, "server-request-logger");
ISOMsg response = req.getResponse(50 * 1000);
if (response != null) {
System.out.println("Req ["+ new String(isoMsg.pack()) + "]");
System.out.println("Res ["+ new String(response.pack()) + "]");
}else{
System.out.println("Timeout");
}
}catch (Exception e) {
e.printStackTrace();
}
}
执行代码后,我得到以下异常:
<log realm="server-request-mux" at="Fri Aug 14 00:26:43 WAT 2015.995">
<muxreceiver>
<exception name="null">
java.lang.NullPointerException
at org.jpos.iso.BaseChannel.createISOMsg(BaseChannel.java:561)
at org.jpos.iso.BaseChannel.createMsg(BaseChannel.java:558)
at org.jpos.iso.BaseChannel.receive(BaseChannel.java:585)
at org.jpos.iso.ISOMUX$Receiver.run(ISOMUX.java:263)
at java.lang.Thread.run(Thread.java:856)
</exception>
</muxreceiver>
</log>
我添加了断点,以找出导致异常的行,并发现只要遇到语句就会发生异常:
ISORequest req = new ISORequest(isoMsg);
我对ISO8583 jpos金融编程比较陌生,我想在Android平台上构建一个应用程序。
如何克服此异常?