快速路线捆绑

Question

我的routes.js文件

module.exports = function(app) {
 //donesn't need to be authorized
 app.use('/login', require('./controllers/session'))

 //will need to be protected
 app.use('/user', auth, require('./controllers/users'))
 app.use('/vineyards', auth, require('./controllers/vineyard'))
 app.use('/varietals', require('./controllers/varietals'))
 app.use('/wines', auth, require('./controllers/wine'))
 app.use('/spectrums', auth, require('./controllers/spectrum'))
 app.use('/lockers', auth, require('./controllers/locker'))
 app.use('/logout', auth, require('./controllers/session')) 
}

＆＃39; auth＆＃39;中间件在我发出get或jsonp请求时起作用，但如果我使用postc错误输出，statusCode为0，并且内容＆＃39; XMLHttpRequestProgressEvent XMLHttpRequestProgressEvent＆＃39;。但是，如果我进入实际的控制器并将auth中间件放在如下的实际帖子上，它就可以工作。

router.post('/', auth, function(req, res) {});

为什么？是否有更好的方法使中间件在所有调用控制器之前运行，然后将其放在每个单独的路径上？