Question

我有一个方法用于显示最高值，并显示它所属的索引号。到目前为止，它已经可以显示最高值，但索引号无法显示。我该怎么做才能让系统显示i值呢？

private void pick_highest_value_here_and_display(ArrayList<Double> value) throws Exception {
    // TODO Auto-generated method stub
    double aa[]=value.stream().mapToDouble(v -> v.doubleValue()).toArray(); 
    double highest=Double.MIN_VALUE;

    System.out.println(highest);
    for(int i=0;i<aa.length;i++)
    {
        if(aa[i]>highest)
        {
            highest=aa[i];
        }
    }
    System.out.println(highest);
    System.out.println(i); // Error: create local variable i
}

Answer 1

您只需修改代码即可保存最大AND i：

private void pick_highest_value_here_and_display(ArrayList<Double> value) throws Exception {
    // TODO Auto-generated method stub
    double aa[]=value.stream().mapToDouble(v -> v.doubleValue()).toArray(); 
    double highest=Double.MIN_VALUE;
    int index=0;
    System.out.println(highest);
    for(int i=0;i<aa.length;i++)
    {
        if(aa[i]>highest)
        {
            index=i;
            highest=aa[i];
        }
    }
    System.out.println(highest);
    System.out.println(index); 
}

Answer 2

您还需要一个变量来存储最高变量的索引。

int highestIndex = 0;//Store index at some other variable
for(int i=0; i< aa.length; i++) {
     if(aa[i] > highest) {
         highest = aa[i];
         highestIndex  = i;
     }
}
System.out.println("Highest value :"+highest+ " found at index :"+highestIndex);

Answer 3

您还必须存储最高值的索引：

private void pick_highest_value_here_and_display(ArrayList<Double> value) throws Exception {
    // TODO Auto-generated method stub
    double aa[]=value.stream().mapToDouble(v -> v.doubleValue()).toArray(); 
    double highest=Double.MIN_VALUE;
    int highestIndex;

    System.out.println(highest);
    for(int i=0;i<aa.length;i++)
    {
        if(aa[i]>highest)
        {
            highest=aa[i];
            highestIndex=i;
        }
    }
    System.out.println(highest);
    System.out.println(highestIndex); // Error: create local variablre i
}

显示数组中的最高值和索引号

3 个答案: