Question

我有4个按钮调用一个功能。根据按下哪个按钮，我需要隐藏按下后调用的功能内部的按钮。我不知道按下了哪个按钮，所以我试图为4个按钮中的每一个分配标签，以便通过标签识别它们并使用开关

我试过这个

            switch sender.tag {
            case 1:
                self.button1.hidden = true
            case 2:
                self.button2.hidden = true
            case 3:
                self.button3.hidden = true
            case 4:
                self.button4.hidden = true

            }

但这不起作用编译器说使用未解析的标识符'sender'

如何正确地做到这一点？

编辑：

整个功能

  if self.allowMistakeVar {

        let mistakeAlert = UIAlertController(title: "Here is title!", message: "message of alert", preferredStyle: .Alert)
        let okay = UIAlertAction(title: "OK", style: .Cancel) { UIAlertAction in

            self.allowMistakeVar = false
            self.allowMistakeButton.enabled = false


            switch sender.tag {
            case answer1Text:
                self.answer1Text.hidden = true
            case answer2Text:
                self.answer2Text.hidden = true
            case answer3Text:
                self.answer3Text.hidden = true
            case answer4Text:
                self.answer4Text.hidden = true

            }

        }

        mistakeAlert.addAction(okay)
        self.presentViewController(mistakeAlert, animated: true, completion: nil )

    } else {

另一个案例.. }

Answer 1

为什么你总是想用标签来确定UIButton？如果被调用函数有一个sender参数，那么你就知道通过这个参数调用函数的UIButton。

func buttonClicked(sender: UIButton)
{
   switch sender {
   case button1: // Do something
   case button2: // Do some other stuff
   ...
   default: ()
   }

}

Answer 2

试试这个，

1）为每个按钮分配标签

Button1.tag=1
Button2.tag=2
Button3.tag=3
Button4.tag=4

2）然后检查您的常用按钮操作

func buttonClicked(sender: UIButton)
{
   switch sender.tag {
   case 1: self.sender.hidden = true //button1
           break;
   case 2: self.sender.hidden = true //button2
           break;
   case 3: self.sender.hidden = true //button3
           break;
   case 4: self.sender.hidden = true //button4
           break;
   default: ()
           break;
   }

}

Answer 3

将您的代码放入如下所示的代码中：

func btnSomeButtonClicked(sender: UIButton)
{
let tag = sender.tag;
       //put your same code here and either use tag variable as i shown or put as you did.
}

- ＆GT;因此，您将很容易获得发件人的财产。

- ＆gt;同时检查您是否忘记为UIButtons提供标签。

Answer 4

I know this has been answered, but if you set this up in IB, then I would recommend you check if the button was pressed by using the @IBOutlet variables as cases.

class SomeView: UIView {
    @IBOutlet weak var buttonA: UIButton!
    @IBOutlet weak var buttonB: UIButton!
    @IBOutlet weak var buttonC: UIButton!

    @IBAction func didHitButton(_ sender: UIButton) {
        switch sender {
        case buttonA:
            doThis()
        }
        case buttonB:
            doThat()
        }
        case buttonC:
            doThisAgain()
        }
        default:
            doNothing()
        }
    }
    ...
}

Now you hook up the buttons in your NIB to each @IBOutlet, and all of the buttons to the one @IBAction didHitButton.

This is pretty straight forward, and you don't have to worry about tags or changing names.

Answer 5

而不是使用switch语句，您可以直接使用发件人。

请注意，您需要指定发件人是UIButton（因此，只有在仅从按钮调用该函数时才会这样做。）

@IBAction func submitButton(sender: UIButton) {

    /* extra code here */

    sender.enabled = false

}

这样可以减少代码，还可以在不更改代码的情况下添加额外的按钮。

Swift - 确定用开关按下哪个按钮

5 个答案: