我有一个在线表单以http post的身份提交数据。 如果没有数据作为帖子发送,它将返回以下错误消息
很抱歉,您提交的表单无效或不再存在。
我使用以下代码使用curl发送http post数据。但是我总是将错误消息作为输出。 如何解决这个问题。我错过了什么。我打印了卷曲请求,并没有发送帖子参数。我该如何解决这个问题? 我的代码如下:
function curlUsingPost($url, $data)
{
$content_type = 'application/x-www-form-urlencoded';
if(empty($url) OR empty($data))
{
return 'Error: invalid Url or Data';
}
//url-ify the data for the POST
$fields_string = '';
foreach($data as $key=>$value) { $fields_string .= $key.'='.$value.'&'; }
$fields_string = http_build_query($data).'\n';
echo $fields_string;
//open connection
$ch = curl_init();
//set the url, number of POST vars, POST data
// curl_setopt($ch, CURLOPT_HTTPHEADER, ['Accept: ' . $content_type]);
curl_setopt($ch, CURLOPT_HTTPHEADER,array($content_type));
curl_setopt($ch,CURLOPT_URL,$url);
curl_setopt($ch,CURLOPT_POST,true);
curl_setopt( $curl_handle, CURLOPT_HTTPHEADER, array( 'Expect:' ) );
curl_setopt($ch,CURLOPT_POSTFIELDS,$fields_string);
curl_setopt($ch,CURLOPT_CONNECTTIMEOUT,10); # timeout after 10 seconds, you can increase it
//curl_setopt($ch,CURLOPT_HEADER,false);
curl_setopt ($ch, CURLOPT_RETURNTRANSFER, 1); # Set curl to return the data instead of printing it to the browser.
curl_setopt($ch, CURLOPT_USERAGENT , "Mozilla/4.0 (compatible; MSIE 8.0; Windows NT 6.1)"); # Some server may refuse your request if you dont pass user agent
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
$info = curl_getinfo($ch);
print_r($info );
//execute post
$result = curl_exec($ch);
//close connection
curl_close($ch);
return $result;
}
$url = 'office.promptip.com:8443/his1.max/Services/Webform.aspx?request=submitwebform&token=202D36560E444E466658461615120F75411B09634C696C6F79454E795E7C7A5154505645414F456C584C17101B443D431D0B654D66686D7C454E795E2D7E5152565341404145625E4213141E4273421E5E66486B666F2A464B7A5B79785F54520645444F15635C454516134422421A0D664A3D68687C454E79587F7D5F52575714424043635E1611181D16704D1D0E654F69696F2A474A7A0A78785807525E45414E406350424016134422421A0D374C6F686C7C44482F59787D5E530150104218426D584316181A4177411B0F';
//echo $url;
$data = [
'C0IFirstName' => 'John Doe',
'C1ILastName' => 'Doe John',
'C2IPosition' =>'Father-Guardian',
'U3I80'=>'8129020464',
'U4I150'=>'johndoe@johndoe.com',
'U5I79'=>'This is the message buddy',
'U6I102' => 'Ann',
'U7I105' =>'Doe',
'U8I52' =>'FS1',
'C9IClientId'=> rand ( 0,100000 ),
'U10I21'=>'Website-Enquiry Form'
];
echo curlUsingPost($url,$data);
答案 0 :(得分:1)
将此添加到您的卷曲请求中:
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
将&
替换为您要求的网址中的&
:
$url = 'office.promptip.com:8443/his1.max/Services/Webform.aspx?request=submitwebform&token=202D36560E444E466658461615120F75411B09634C696C6F79454E795E7C7A5154505645414F456C584C17101B443D431D0B654D66686D7C454E795E2D7E5152565341404145625E4213141E4273421E5E66486B666F2A464B7A5B79785F54520645444F15635C454516134422421A0D664A3D68687C454E79587F7D5F52575714424043635E1611181D16704D1D0E654F69696F2A474A7A0A78785807525E45414E406350424016134422421A0D374C6F686C7C44482F59787D5E530150104218426D584316181A4177411B0F';
首先,您要求提供错误的网址,这可能是从某些HTML文档中复制的。通常情况下,&
实体将由HTML解释器替换为&
char,但这不适用于curl,您必须手动替换实体。
服务器也返回
很抱歉,您提交的表单无效或无效 存在的时间越长。
每个结束响应正文中的每个请求。但是对于成功请求,它还提供Location
标头。通常,浏览器会跟随此位置,发出第二个请求并显示成功消息。您必须告诉cURL与curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true)
完全相同。