Question

我目前的查询如下：

create table Report as
select distinct
    a.Var1,
    count(distinct b.Var2) as Var2,

from tbl1 a

inner join tbl2 b
on a.Var3=b.Var3 and a.Var4=b.Var4

inner join tbl3 c
on c.Var3=b.Var3

group by a.Var1
order by Var2 desc
;

这很好用，我得到以下结果

VAR1 ---------------------------------------------- -Var2 ------------------------------------------------ ------------------------ COCA COLA ZERO CAN 8X330ML ----- 19279 --------------------------------------- --------------------------- BULK VEGETABLES ------------------------ 11723 ----------- ------------ ----------------------------------------- BULK FRUITS --------------------------------- 10496 -------------- ------------------------------------------------ BREAD ------------------------------------------- 6605 ----- -------------------------------------------------- -----------

我的问题是我想添加第三列来计算Var2 / max（Var2）的百分比。请记住，此最大值始终位于第一行（如果有帮助）。

所以我希望我的结果是

VAR1 ---------------------------------------------- Var2 --- Var3

COCA COLA ZERO CAN 8X330ML ----- 19279 -100％

BULK VEGETABLES ------------------------ 11723 --60.81％

BULK FRUITS --------------------------------- 10496-- 54.44％

BREAD ------------------------------------------- 6605-- - 34.26％

我试过

create table Report as
   select distinct
   a.Var1,
   count(distinct b.Var2) as Var2,
   calculated Var2/max(calculated Var2)

但我收到错误＆＃34;不支持以这种方式嵌套的摘要函数。＆＃34;

Answer 1

您始终可以嵌套查询：

create table Report as  
select  
    Var1,  
    Var2,  
    Var2/max(Var2) as pct_Var2  
from (  
    select distinct  
        a.Var1,  
        count(distinct b.Var2) as Var2  
    from  
        (...)  
    group by a.Var1  
)

Proc SQL，计算值的聚合

1 个答案: