我无法理解为什么我的功能不起作用,也许我选择错了?
HTML:
SELECT A.TAX_YEAR,A.MONTH,A.EMPLOYER_CODE
,(
SELECT SUM(AMOUNT)
FROM V_HR_PP_PROCESS_DATA
WHERE EMPLOYER_CODE = A.EMPLOYER_CODE
AND TAX_YEAR = A.TAX_YEAR
AND PROCESS_MONTH = A.MONTH
AND EMPLOYEE_ID IN (
SELECT EMPLOYEE_ID
FROM I_HR_EMP_EMPLOYMENT_DTL
WHERE EMPLOYER_CODE = A.EMPLOYER_CODE
AND CONTRACT_TERM = 'P'
)
AND PROCESS_MONTH BETWEEN 1
AND 10
AND PD_CODE = 'Z500'
) AS GROSS_PERMANENT
,b.EMPLOYEE_NAME AS employeename
,(
SELECT SUM(AMOUNT)
FROM V_HR_PP_PROCESS_DATA
WHERE EMPLOYER_CODE = A.EMPLOYER_CODE
AND TAX_YEAR = A.TAX_YEAR
AND PROCESS_MONTH = A.MONTH
AND EMPLOYEE_ID IN (
SELECT EMPLOYEE_ID
FROM I_HR_EMP_EMPLOYMENT_DTL
WHERE EMPLOYER_CODE = A.EMPLOYER_CODE
AND CONTRACT_TERM = 'F'
)
AND PROCESS_MONTH BETWEEN 1
AND 10
AND PD_CODE = 'Z500'
) AS GROSS_CASUAL
FROM I_HR_SYS_DATE_MONTHLY A
INNER JOIN I_HR_EMPLOYEE_MASTER b ON b.EMPLOYER_CODE = A.EMPLOYER_CODE
group by A.MONTH,A.TAX_YEAR,A.EMPLOYER_CODE,b.EMPLOYEE_NAME
我想在用户点击第三个单选按钮时显示第二个div。 我试图改变剧本的位置,但我不认为这是问题所在。 我确信这是一个微不足道的问题。 它没有用!
<html>
{% include head.html %}
<body id="general">
<header>
{% include navbar.html %}
<script>
$('input[name=optradio])'.click(function () {
if (this.id == "showdiv") {
$("#onsaanbod").show('slow');
} else {
$("#onsaanbod").hide('slow');
}
});
</script>
</header>
<div class="container-fluid">
<!-- contenttop -->
<div class="row" style="padding-top: 3%; padding-bottom: 3%;" >
{% include /getaquote/contenttop-getaquote.html %}
</div>
<div class="col-md-12 col-lg-10 col-lg-offset-2">
<div class="row">
<div class="col-md-12">
<p> content </p>
</div>
</div>
<div class="row">
<div class="col-md-12">
<hr>
</div>
</div>
<!-- start-form -->
<!-- Volume -->
<div class="row">
<div class="col-md-6">
<p> content </p>
</div>
<div class="col-md-6">
<div class="controls">
<form id='form-id'>
<div class="radio">
<label><input type="radio" name="optradio">Meer dan 1000 per jaar</label>
</div>
<div class="radio">
<label><input type="radio" name="optradio">Tussen 500 en 1000 per jaar</label>
</div>
<div class="radio">
<label><input type="radio" name="optradio" id="showdiv">Minder dan 500 per jaar</label>
</div>
</form>
</div>
</div>
</div>
<div class="row" id="onsaanbod" style='display:none'>
<div class="col-md-12">
<h1 class="titlel1"> content </h1>
<p> content </p>
</div>
</div>
</div>
答案 0 :(得分:3)
有一个错字:
$('input[name=optradio])'.click
$('input[name=optradio]').click
和强>
您应该将js移动到正文的底部,或者将其包装在$(document).ready()方法中
$(document).ready(function(){
$('input[name=optradio]').click(function () {
if (this.id == "showdiv") {
$("#onsaanbod").show('slow');
} else {
$("#onsaanbod").hide('slow');
}
});
});
当你将che click
监听器应用于它时,确保元素存在
答案 1 :(得分:2)
您必须将代码包装在
中$(document).ready(function(){
//Code
});
这将确保脚本在页面加载后触发,从而具有可供使用的资源。在您的情况下,您的代码将如下所示:
$(document).ready(function(){
$('input[name=optradio]').click(function () {
if (this.id == "showdiv") {
$("#onsaanbod").show('slow');
} else {
$("#onsaanbod").hide('slow');
}
});
});
答案 2 :(得分:0)
您必须将代码包装成:
// A $( document ).ready() block.
$( document ).ready(function() {
console.log( "ready!" );
});
答案 3 :(得分:0)
将整个代码包装在内:
$(document).ready(function(){
// Here..
});
只有在加载所有DOM元素后才会执行。