Question

我想要一种方法，使用我的用户名或我的电子邮件登录我的Parse帐户。我现在的代码只能使用我的用户名。我想知道一种识别文本字段是否包含用户名或电子邮件的方法。

这是代码，

private class SignInOnClickListener implements View.OnClickListener {

    @Override
    public void onClick(View v) {
        // Get the username and password from the view
        final String username_email = mUsernameEmailEtxt.getText().toString().toLowerCase();
        final String password = mPasswordEtxt.getText().toString();

        if (isFormInputValid(username_email, password)) {
            if (android.util.Patterns.EMAIL_ADDRESS.matcher(username_email).matches()) { // HERE!
                final String email = mUsernameEmailEtxt.getText().toString();
                ParseUser.logInInBackground(email, password, new LogInCallback() {
                    public void done(ParseUser user, ParseException e) {
                        if (user != null) {
                            // Hooray! The user is logged in.
                            Intent intent = new Intent(getBaseContext(), MainActivity.class).addFlags(Intent.FLAG_ACTIVITY_NO_HISTORY | Intent.FLAG_ACTIVITY_CLEAR_TASK);
                            startActivity(intent);
                            finish();
                        }
                    }
                });
            } else {
                ParseUser.logInInBackground(username_email, password, new LogInCallback() {

                    public void done(ParseUser user, ParseException e) {
                        if (user != null) {
                            // Hooray! The user is logged in.
                            Intent intent = new Intent(getBaseContext(), MainActivity.class).addFlags(Intent.FLAG_ACTIVITY_NO_HISTORY | Intent.FLAG_ACTIVITY_CLEAR_TASK);
                            startActivity(intent);
                            finish();
                        } else {
                            findViewById(R.id.error).setVisibility(View.VISIBLE);
                        }
                    }
                });
            }
        }
    }
}

private class SignInOnClickListener implements View.OnClickListener {

    @Override
    public void onClick(View v) {
        // Get the username and password from the view
        final String username_email = mUsernameEmailEtxt.getText().toString().toLowerCase();
        final String password = mPasswordEtxt.getText().toString();

        if (isFormInputValid(username_email, password)) {
            if (android.util.Patterns.EMAIL_ADDRESS.matcher(username_email).matches()) { // HERE!
                final String email = mUsernameEmailEtxt.getText().toString();
                ParseUser.logInInBackground(email, password, new LogInCallback() {
                    public void done(ParseUser user, ParseException e) {
                        if (user != null) {
                            // Hooray! The user is logged in.
                            Intent intent = new Intent(getBaseContext(), MainActivity.class).addFlags(Intent.FLAG_ACTIVITY_NO_HISTORY | Intent.FLAG_ACTIVITY_CLEAR_TASK);
                            startActivity(intent);
                            finish();
                        }
                    }
                });
            } else {
                ParseUser.logInInBackground(username_email, password, new LogInCallback() {

                    public void done(ParseUser user, ParseException e) {
                        if (user != null) {
                            // Hooray! The user is logged in.
                            Intent intent = new Intent(getBaseContext(), MainActivity.class).addFlags(Intent.FLAG_ACTIVITY_NO_HISTORY | Intent.FLAG_ACTIVITY_CLEAR_TASK);
                            startActivity(intent);
                            finish();
                        } else {
                            findViewById(R.id.error).setVisibility(View.VISIBLE);
                        }
                    }
                });
            }
        }
    }
}

更新：我已经记录日志并进行了一些更改（来源：@kevin），检测到电子邮件但拒绝使用它登录。

这是代码，

 private class SignInOnClickListener implements View.OnClickListener {

    @Override
    public void onClick(View v) {
        // Get the username and password from the view
        final String username_email = mUsernameEmailEtxt.getText().toString().toLowerCase();
        final String password = mPasswordEtxt.getText().toString();
        final String email = mUsernameEmailEtxt.getText().toString().toLowerCase();

        if (isFormInputValid(username_email, password)) {
            if (username_email.indexOf('@') != -1) { // HERE!
                Log.d("detector", "username_email detected as email:" + email.toString());
                ParseUser.logInInBackground(email, password, new LogInCallback() {
                    public void done(ParseUser user, ParseException e) {
                        if (user != null) {
                            // Hooray! The user is logged in.
                            Intent intent = new Intent(getBaseContext(), MainActivity.class).addFlags(Intent.FLAG_ACTIVITY_NO_HISTORY | Intent.FLAG_ACTIVITY_CLEAR_TASK);
                            startActivity(intent);
                            finish();
                        }
                    }
                });
            } else {
                Log.d("detector", "username_email detected as username:" + username_email.toString());
                ParseUser.logInInBackground(username_email, password, new LogInCallback() {
                    public void done(ParseUser user, ParseException e) {
                        if (user != null) {
                            // Hooray! The user is logged in.
                            Intent intent = new Intent(getBaseContext(), MainActivity.class).addFlags(Intent.FLAG_ACTIVITY_NO_HISTORY | Intent.FLAG_ACTIVITY_CLEAR_TASK);
                            startActivity(intent);
                            finish();
                        } else {
                            findViewById(R.id.error).setVisibility(View.VISIBLE);
                            Log.d("error", "username or email invalid");
                        }

                    }
                });
            }

        }
    }
}

Answer 1

这并不难做，您应该使用Android中已提供的内置模式来完美检查电子邮件ID。

public final static boolean isEmailIDValid(CharSequence email) {
    if (email == null) 
        return false;

    return android.util.Patterns.EMAIL_ADDRESS.matcher(email).matches();
}

在API 8之上的所有Android版本上都不那么复杂和完美。我在任何支持API 14及更高版本的应用程序中都使用过此版本，并且从未遇到过任何问题。

Answer 2

验证电子邮件地址extremely complicated。那篇文章建议您只是尝试向该地址发送一封电子邮件，这不完全符合您的使用案例，但请按照这些思路进行思考。也许做一个粗略的验证，比如测试该字段是否包含@，如果是，请尝试将其用作电子邮件。

Answer 3

这不是那么复杂，你可以尝试this，如果电子邮件只包含低毛细管字母，@和“。”，它会给你真实的。

Answer 4

使用Apache Validation Library。它小巧，简洁，做到了工作。

userEditText.addTextChangedListener(new TextWatcher() {
    public void beforeTextChanged(CharSequence s, int start, int count, int after) {

    }

    public void onTextChanged(CharSequence s, int start, int before, int count) {
        textView.setVisibility(View.VISIBLE);
    }

    public void afterTextChanged(Editable s) {
        EmailValidator emailValidator = EmailValidator.getInstance();
        if (!emailValidator.isValid(s.toString())) {
          //Is Email
        } else {
         //Is username   
        }
    }
});

注意：希望您已考虑到边缘情况，因为您的用户名也可能是根据您的要求判断的电子邮件

从edittext Android

4 个答案: