Question

我是春天的初学者。我浏览了这个，只得到this note

我的两个xml文件：

one.xml

<?xml version="1.0" encoding="UTF-8"?>
    <!DOCTYPE properties SYSTEM "http://java.sun.com/dtd/properties.dtd">
<properties>
    <entry key="url">stackoverflow.com/</entry>
</properties>

second.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
       xmlns:security="http://www.springframework.org/schema/security"
       xmlns:context="http://www.springframework.org/schema/context"
       xsi:schemaLocation="http://www.springframework.org/schema/beans 
        http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
        http://www.springframework.org/schema/security
    http://www.springframework.org/schema/security/spring-security-3.0.xsd"            
 >

<context:property-placeholder location="classpath:config.xml" />

<security:authentication-manager>
  <security:ldap-server url="${url}" 
    manager-dn="XXX" manager-password="XXX" />
</beans>

我得到的例外是：

无法找到元素“context：property-placeholder”的声明

Answer 1

对于上下文模式命名空间，您没有指定模式位置。像这样改变豆类声明。

<beans xmlns="http://www.springframework.org/schema/beans"
   xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
   xmlns:security="http://www.springframework.org/schema/security"
   xmlns:context="http://www.springframework.org/schema/context"
   xsi:schemaLocation="http://www.springframework.org/schema/beans 
    http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
    http://www.springframework.org/schema/security
    http://www.springframework.org/schema/security/spring-security-3.0.xsd
    http://www.springframework.org/schema/context
    http://www.springframework.org/schema/context/spring-context-3.0.xsd">

无法找到元素“context：property-placeholder”的声明

1 个答案: